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amm1812
3 years ago
7

What is the Bayer process explain it

Chemistry
1 answer:
Vlada [557]3 years ago
7 0

Answer:

The Bayer process is the principal industrial means of refining bauxite to produce alumina (aluminium oxide) and was developed by Carl Josef Bayer. Bauxite, the most important ore of aluminium, contains only 30–60% aluminium oxide (Al2O3), the rest being a mixture of silica, various iron oxides, and titanium dioxide.

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What is steel and why is it better than iron?
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Steel is practically one of the worlds most important metals to use in construction, it is harder and stronger than iron can be. You can say iron is the base metal of steel, if you need more info, just ask :>
5 0
3 years ago
If you had 1.50 g of ZnSO4.7H20, zinc sulfate septahydrate, how many grams of water will there be?
MariettaO [177]

Answer:

There will be 1.50 gram of water

5 0
2 years ago
What group is the element NITROGEN in? 1 Group 4<br> 2 Group 5<br> 3 Group 2<br> 4 Group 8
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3 0
2 years ago
Read 2 more answers
A chemical reaction produced 10.1 cm3 of nitrogen gas at 23 °C and 746 mmHg. What is the volume of this gas if the temperature a
adell [148]

Answer:

volume of gas = 9.1436cm³

Explanation:

We will only temperature from °C to K since the conversion is done by the addition of 273 to the Celsius value.

Its not necessary to convert pressure and volume as their conversions are done by multiplication and upon division using the combined gas equation, the factors used in their conversions will cancel out.

V1 =10.1cm³ , P1 =746mmHg,     T1=23°C =23+273=296k

V2 =? ,   P2 =760mmmHg ,     T2=0°C = 0+273 =273K

Using the combined gas equation to calculate for V2;

\frac{V1P1}{T1}=\frac{V2P2}{T2} \\ re-arranging, \\V2 =\frac{V1P1T2}{P2T1}

V2 =\frac{10.1*746*273}{760*296}

V2=9.1436cm³

6 0
3 years ago
How do I calculate the standard enthalpy change for the following reaction at 25 °C ?
ladessa [460]
MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g) 

Using the standard enthalpies of formation given in the source below: 

(−601.24 kJ) + (2 x −92.30 kJ) − (−641.8 kJ) − (−285.8 kJ) = +141.76 kJ 
So: 

MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g), ΔH = +141.76 kJ
4 0
3 years ago
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