All categories

2 years ago

23492u undergoes alpha decay. what is the atomic number of the resulting element.

1 answer:

4 0

Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.

You might be interested in

Which electron configuration is impossible?

Verizon [17]

Answer:

MP hippopotamus

Explanation: I'm in the fifth grade so yeah I really don't know this so I'm just going to say some random stuff and white cheddar mac and cheese warm TV perfect back MD 11443 to 2885 eleven 12:20 to 11 132 0.24 answer

7 0

1 year ago

In a nuclear reactor, when the control rods are lowered between the fuel rods, they slow the fission reactions.

rosijanka [135]

True when the boron control rods are lowered it slows the reaction

5 0

2 years ago

Read 2 more answers

Equilibrium describes the balance that results from a forward and reverse reaction proceeding at equal rates. Since reaction rat

Delvig [45]

Answer:

b) the reaction proceeds to a new equilibrium in the direction that offsets the change.

Explanation:

According to Le Chatelier's principle, when a system experiences a constraint such as a change in pressure, temperature or concentration, the system will readjust itself in order to annul the constraint.

This simply means that when temperature, concentration or pressure is changed, a new equilibrium position is reached in order to offset the changes in the system.

5 0

2 years ago

Which would result in radioactive decay? Check all that apply

Gekata [30.6K]

6+2=115 and its good it took test

4 0

2 years ago

Read 2 more answers

What is the pH of 0.10 M NaF(aq). The Ka of HF is 6.8 x 10-4

dsp73

Given information:

Concentration of NaF = 0.10 M

Ka of HF = 6.8*10⁻⁴

To determine:

pH of 0.1 M NaF

Explanation:

NaF (aq) ↔ Na+ (aq) + F-(aq)

[Na+] = [F-] = 0.10 M

F- will then react with water in the solution as follows:

F- + H2O ↔ HF + OH-

Kb = [OH-][HF]/[F-]

Kw/Ka = [OH-][HF]/[F-]

At equilibrium: [OH-]=[HF] = x and [F-] = 0.1 - x

10⁻¹⁴/6.8*10⁻⁴ = x²/0.1-x

x = [OH-] = 1.21*10⁻⁶ M

pOH = -log[OH-] = -log[1.21*10⁻⁶] = 5.92

pH = 14 - pOH = 14-5.92 = 8.08

Ans: (b)

pH of 0.10 M NaF is 8.08

6 0

2 years ago