Answer:
GAY-LUSSAC'S LAW.
Explanation:
P1 = 765 torr
T1 = 23°C = 296K
P2 = 560. torr
T2 = ?
(765 torr)/(296K) = (560. torr)/ T2
T2 = 226 K = -57°C
<h2>Heptene formed is -</h2><h2>

</h2>
Explanation:
The two possibilities when the peroxide is not present
+ HBr →
In presence peroxide,
≡
+ HBr →
- When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.
- This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
- One mole of HBr adds to one mole of 1-heptane.
- The structure of heptene formed is -

Answer:
-372000 J or -372 KJ
Explanation:
We have the electrochemical reaction as;
Mg(s) + Fe^2+(aq)→ Mg^2+(aq) + Fe(s)
We must first calculate the E∘cell from;
E∘cathode - E∘anode
E∘cathode = -0.44 V
E∘anode = -2.37 V
Hence;
E∘cell = -0.44 V -(-2.37 V)
E∘cell = 1.93 V
n= 2 since two electrons were transferred
F=96,500C/(mol e−)
ΔG∘=−nFE∘
ΔG∘= -( 2 * 96,500 * 1.93)
ΔG∘= -372000 J or -372 KJ
Answer:
Molecular Formula = C6H6
Explanation:
Empirical Formular = CH
Molar Mass = 78.11
Molecular Formular = ?
The Formular relating these parameters is given as;
(Empirical Formula)n = Molecular Formular
where n = Number of moles
CH = 12.0107 + 1.00784 = 13.01854
(13.01854)n = 78.11
n = 78.11 / 13.01854
n = 5.9999 ≈ 6
Molecular Formula = C6H6