What temperature is absolute zero? A. OK B. 0°F O C. O molecules D. 0°C

Chemistry

2 answers:

KiRa [710]4 years ago

6 0

Answer:

o k

Explanation:

ok ok .......o k....ok aaaaaaa

Wittaler [7]4 years ago

3 0

Answer:

the absolute zero temperature is D o°c

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if a 2.0g sample of water at 5.0celcius absorbs 21.8Joules of energy, the temprature of the sample will be raised by

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You'd use the temperature change equation. The specific heat of water is always 4.18J/(g °C).
Equation to use: q=mCΔT

21.8=(2.0)(4.18)(Tf-5)
21.8=(8.36)(Tf-5)
21.8/8.36=Tf-5
2.61=Tf-5
2.61+5=Tf
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Since you want to know how many °C it raises, you wouldn't pay attention to the last 2 steps, however if you need to know the final temp, you want to go to the last step.

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3 years ago

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The atomic radii of a divalent cation and a monovalent anion are 0.62 nm and 0.121 nm, respectively. (a) Calculate the force of

Zepler [3.9K]

Answer:

$\boxed{8.4\times 10^{-10} \text{ N}}$

Explanation:

The formula for the force exerted between two ions is

$F = \dfrac{kq_{1}q_{2}}{r^{2}} = \dfrac{kz_{1}z_{2}e^{2}}{r^{2}}$

where the Coulomb constant

k = 8.988 × 10⁹ N·m·C⁻²

Data:

z₁ = +2; r₁ = 0.62 nm

z₂ = -1; r₂ = 0.121 nm

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r = r₁ + r₂ = 0.62 + 0.121 = 0.741 nm

$F =\dfrac{8.988 \times 10^{9} \text{ N $\cdot$ m$^{2} \cdot$ C$^{-2}$} \times 2 \times (-1) \times ( 1.602 \times 10^{-19} \text{ C})^{2}}{(0.741 \times 10^{-9} \text{ m})^{2}}\\\\ = -\mathbf{8.4\times 10^{-10}} \textbf{ N}\\\text{The attractive force between the ions is } \boxed{\mathbf{8.4\times 10^{-10}} \textbf{ N}}$

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3 years ago

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Anettt [7]

Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺

Explanation :

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

(a) $CO_2$