The two properties which are used to define matter are that it has mass and it takes up space. The other properties do not necessarily apply to each matter. Such some matter can be a conductor of heat (such as metal) and some not (such as non metals). Likewise, some matter can be buoyant and float on liquid of density more than it but others would not on the liquids of density less than it. In-fact not all the matters are conductors of energy (such as heat, sound, electricity) or at-least a very poor conductor of energy and tend to find application as insulating agents (non conductors). So the only thing which is necessarily true is that the matter would definitely have mass in even their minutest form as atom and would take up some space.

3 0

4 years ago

To use the gas law constant R=0.0821 the unit for temp should be kelvin and the unit for pressure should be atmospheres True or

hoa [83]

It is crucial to match your units of Pressure, Volume, number of mole, and Temperature with the units of R. If you use the first value of R, which is 0.082057 L atm mol-1K-1, your unit for pressure must be atm, for volume must be liter, for temperature must be Kelvin.

7 0

3 years ago

Read 2 more answers

1. All of the following energy resources are fossil fuels except

solong [7]

C. Biomass is the correct answer

4 0

3 years ago

Find the mass in grams of 3.00 x 1023 molecules of F2

LUCKY_DIMON [66]

<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})$
Multiply: $\displaystyle 18.9306 \ g \ F_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0

3 years ago