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melamori03 [73]
3 years ago
7

Collision level 17 answers

Chemistry
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:: an act or instance of colliding : clash. 2 : an encounter between particles (such as atoms or molecules) resulting in exchange or transformation of energy. Other Words from collision Synonyms Choose the Right Synonym Example Sentences Learn More about collision.

Explanation:

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Is carbon dioxide a good absorber of infrared radiation
kompoz [17]

yes.

stream neo zone the album by nct127 on spotify

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3 years ago
A chemical or physical change that takes in heat from its surroundings is an exothermic process an explosion an endothermic proc
Setler79 [48]
Is this a true or false question?
6 0
4 years ago
Read 2 more answers
Which statement is true about AC?
AysviL [449]

According to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

<h3>What is AC?</h3>

It is the flow of electric charges through a conductor is called electric current, if said flow of electric current varies in direction from time to time, we speak of alternating current.

Subatomic particles such as protons and electrons have an electrical charge, a physical property that is manifested by the repulsive and attractive forces that exist between them in AC the electrical charge moves back and forth.

Therefore, we can conclude that according to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

Learn more about AC here: brainly.com/question/11695848

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3 0
1 year ago
For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v
Ierofanga [76]

Answer:

\Delta G^o=-5.4032 kJ

The temperature for \Delta G^o=0[/tex is [tex]T=328.6 K

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

\Delta G^o=\Delta H^o + T*\Delta S^o

Where:

\Delta G^o is Gibbs's energy in kJ

\Delta H^o is the enthalpy in kJ

\Delta S^o is the entropy in kJ/K

T is the temperature in K

Solving:

\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K

\Delta G^o=-5.4032 kJ

For \Delta G^o=0:

0=\Delta H^o - T*\Delta S^o

\Delta H^o= T*\Delta S^o

T=\frac{\Delta H^o}{\Delta S^o}

T=\frac{-58.03 kJ}{-0.1766 kJ/K}

T=328.6 K

3 0
3 years ago
Read 2 more answers
Hospital patients are administered oxygen from an pressurized
Nataly_w [17]

Answer:

110L

Explanation:

Boyle's Law states that P1×V1=P2×V2

Volume is indirectly proportional to Pressure so P×V is constant

P1=55atm

V1=6L

P2=3atm

V2 is to be found

P1×V1=P2×V2

6×55=3×V2

330=3×V2

Answer: V2=110L

8 0
3 years ago
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