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KATRIN_1 [288]
3 years ago
14

A chemical or physical change that takes in heat from its surroundings is an exothermic process an explosion an endothermic proc

ess a phase change
Chemistry
2 answers:
lilavasa [31]3 years ago
7 0
Hello!

The Correct Answer to: 

"<span>A chemical or physical change that takes in heat from its surroundings is"

Is 100% Option "B" an explosion.

(Ps. I did this yesterday :) )


Hope this Helps! Have A Wonderful Day! :)</span>
Setler79 [48]3 years ago
6 0
Is this a true or false question?
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True or false. elements in the same period have the same number of valence electrons
saul85 [17]
False. elements in the same period have the same number of shells while elements in the same group have the same number of valence electrons.
4 0
3 years ago
Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10
nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8


<h2><u>Answer: [OH-] = 1.3 x 10^-8</u></h2>
4 0
3 years ago
A mineral that breaks into irregular pieces is said to show which of the following?
Ray Of Light [21]
The original options for this question were cleavage, luster and hardness. The answer would be cleavage.
4 0
3 years ago
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How many grams of salt are in 1 kilogram of seawater with average salinity? quizzlet?
Degger [83]
<span>35 grams The average salinity of seawater is 35 parts per thousand, so multiply the mass of seawater provided by 0.035 and you'll get the amount of salt (mostly sodium chloride) dissolved in it. So 1000 g * 0.035 = 35 g Therefore in 1 kilogram of seawater with average salinity, there is 35 grams of salt.</span>
5 0
3 years ago
Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come
Elden [556K]

Answer:

B

Explanation:

For solving this we need a heat balance

Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}

By changing the corresponding relations, we have

m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\

By cancelling similar factor, we obtain

\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\

Which means that the change of temperature in A is twice the change of B

3 0
3 years ago
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