Answer:
29274.93096 m/s
![2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
![-5.39323\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.39323%5Ctimes%2010%5E%7B33%7D%5C%20J)
![2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
![-5.21594\times 10^{33}](https://tex.z-dn.net/?f=-5.21594%5Ctimes%2010%5E%7B33%7D)
Explanation:
= Distance at perihelion = ![1.471\times 10^{11}\ m](https://tex.z-dn.net/?f=1.471%5Ctimes%2010%5E%7B11%7D%5C%20m)
= Distance at aphelion = ![1.521\times 10^{11}\ m](https://tex.z-dn.net/?f=1.521%5Ctimes%2010%5E%7B11%7D%5C%20m)
= Velocity at perihelion = ![3.027\times 10^{4}\ m/s](https://tex.z-dn.net/?f=3.027%5Ctimes%2010%5E%7B4%7D%5C%20m%2Fs)
= Velocity at aphelion
m = Mass of the Earth = 5.98 × 10²⁴ kg
M = Mass of Sun = ![1.9889\times 10^{30}\ kg](https://tex.z-dn.net/?f=1.9889%5Ctimes%2010%5E%7B30%7D%5C%20kg)
Here, the angular momentum is conserved
![L_p=L_a\\\Rightarrow r_pv_p=r_av_a\\\Rightarrow v_a=\frac{r_pv_p}{r_a}\\\Rightarrow v_a=\frac{1.471\times 10^{11}\times 3.027\times 10^{4}}{1.521\times 10^{11}}\\\Rightarrow v_a=29274.93096\ m/s](https://tex.z-dn.net/?f=L_p%3DL_a%5C%5C%5CRightarrow%20r_pv_p%3Dr_av_a%5C%5C%5CRightarrow%20v_a%3D%5Cfrac%7Br_pv_p%7D%7Br_a%7D%5C%5C%5CRightarrow%20v_a%3D%5Cfrac%7B1.471%5Ctimes%2010%5E%7B11%7D%5Ctimes%203.027%5Ctimes%2010%5E%7B4%7D%7D%7B1.521%5Ctimes%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20v_a%3D29274.93096%5C%20m%2Fs)
Earth's orbital speed at aphelion is 29274.93096 m/s
Kinetic energy is given by
![K=\frac{1}{2}mv_p^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(3.027\times 10^{4})^2\\\Rightarrow K=2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv_p%5E2%5C%5C%5CRightarrow%20K%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%283.027%5Ctimes%2010%5E%7B4%7D%29%5E2%5C%5C%5CRightarrow%20K%3D2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
Kinetic energy at perihelion is ![2.73966\times 10^{33}\ J](https://tex.z-dn.net/?f=2.73966%5Ctimes%2010%5E%7B33%7D%5C%20J)
Potential energy is given by
![P=-\frac{GMm}{r_p}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.471\times 10^{11}}\\\Rightarrow P=-5.39323\times 10^{33}](https://tex.z-dn.net/?f=P%3D-%5Cfrac%7BGMm%7D%7Br_p%7D%5C%5C%5CRightarrow%20P%3D-%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.989%5Ctimes%2010%5E%7B30%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%7D%7B1.471%5Ctimes%20%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20P%3D-5.39323%5Ctimes%2010%5E%7B33%7D)
Potential energy at perihelion is ![-5.39323\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.39323%5Ctimes%2010%5E%7B33%7D%5C%20J)
![K=\frac{1}{2}mv_a^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(29274.93096)^2\\\Rightarrow K=2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv_a%5E2%5C%5C%5CRightarrow%20K%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%2829274.93096%29%5E2%5C%5C%5CRightarrow%20K%3D2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
Kinetic energy at aphelion is ![2.56249\times 10^{33}\ J](https://tex.z-dn.net/?f=2.56249%5Ctimes%2010%5E%7B33%7D%5C%20J)
Potential energy is given by
![P=-\frac{GMm}{r_a}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.521\times 10^{11}}\\\Rightarrow P=-5.21594\times 10^{33}](https://tex.z-dn.net/?f=P%3D-%5Cfrac%7BGMm%7D%7Br_a%7D%5C%5C%5CRightarrow%20P%3D-%5Cfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.989%5Ctimes%2010%5E%7B30%7D%5Ctimes%205.98%5Ctimes%2010%5E%7B24%7D%7D%7B1.521%5Ctimes%2010%5E%7B11%7D%7D%5C%5C%5CRightarrow%20P%3D-5.21594%5Ctimes%2010%5E%7B33%7D)
Potential energy at aphelion is ![-5.21594\times 10^{33}\ J](https://tex.z-dn.net/?f=-5.21594%5Ctimes%2010%5E%7B33%7D%5C%20J)
What is horoscope?
A forecast of a person's future, typically including delineation of character and circumstances, based on the relative positions of the stars and planets at the time of that person's birth.
*A short forecast for people born under a particular sign, especially as published in a newspaper or magazine.
*A birth chart.
What is its uses?
It can also be calculated for an event, a question, and even a country. Symbols are used to represent planets, signs, and geometric connections called aspects. In most cases, the horoscope in Western astrology is drawn on a circular wheel.
Answer:
The specific latent heat of a substance is the amount of energy required to change the state of one kilo of the substance without change in it temperature.The latent heat of vaporization or evaporation is the heat given to some mass to convert if from the liquid to the vapor phase.
Answer:
The distance of separation is decreased
Explanation:
From Cuolomb's law, we know that the strength of charge is inversely proportional to the distance of separation between the charges. To mean that increasing the distance let's say from 2m to 3 m would mean initial strength getting form 1/4 to 1/9 which is a decrease. The vice versa is true hence the force of repulsion can increase only when we decrease the distance of separation.