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Dovator [93]
2 years ago
14

Three capillary tubes with different radius (r1=1.0mm, r2=0.1mm, r3=0.01mm) are inserted into the same cup of water. The surface

tension of water is measured to be 72.3 mN/m. The contact angle of water in each tube is 30°. Calculate the height of water rising in the three capillary tubes
Engineering
1 answer:
kobusy [5.1K]2 years ago
4 0

Answer:

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Explanation:

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6 0
3 years ago
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Milk has a density of as much as 64.6 lb/ft3. What is the gage pressure at the bottom of the straw 6.1 inches deep in the milk?
gregori [183]

Answer:

Explanation:

1 inch is 0.0833333feet

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64.6 = mass/0.50833

mass = 64.6 x 0.5083 =32.83618lb

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What does this middle button on the middle of my Chevrolet equinox steering wheel mean?
almond37 [142]

Answer:

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7 0
3 years ago
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Sam decides to remove his oversized hooded jacket before he works near the pto driveline is it safe or unsafe
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4 0
2 years ago
Fully developed conditions are known to exist for water flowing through a 25-mm-diameter tube at 0.01 kg/s and 27 C. What is the
Irina18 [472]

Answer:

0.0406 m/s

Explanation:

Given:

Diameter of the tube, D = 25 mm = 0.025 m

cross-sectional area of the tube = (π/4)D² = (π/4)(0.025)² = 4.9 × 10⁻⁴ m²

Mass flow rate = 0.01 kg/s

Now,

the mass flow rate is given as:

mass flow rate = ρAV

where,

ρ is the density of the water = 1000 kg/m³

A is the area of cross-section of the pipe

V is the average velocity through the pipe

thus,

0.01 = 1000 × 4.9 × 10⁻⁴ × V

or

V = 0.0203 m/s

also,

Reynold's number, Re = \frac{VD}{\nu}

where,

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thus,

Re = \frac{0.0203\times0.025}{0.833\times10^{-6}}

or

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thus,

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