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Marrrta [24]
3 years ago
7

For the following problems, identify the substance as either an element, a compound, or a mixture. Write E for Element, C for co

mpound, and M for mixture. 34. Silicon ___E__ 35. Salad dressing __M___ 36. Table Salt (NaCl) __C___ 37. Oatmeal with apples and raisins_____ 38. Lithium _____ 39. Copper Sulfate (CuSO4) _____
Chemistry
1 answer:
andre [41]3 years ago
3 0

Answer:

Explanation:

34. E

35. M

36. C

37. M

38. E

39. C

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Pretty sure non polar bc it’s equal
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The path urine takes after it is formed until it leaves the body is the urethra, urinary bladder, and finally the ureter. True F
Vlad1618 [11]

Answer:

False

Explanation:

The urine is produced in the kidneys, each one of the kidneys is connected to a ureter.  The ureter is a tube that propels the excreted urine to the urinary bladder. The urinary bladder is a deposit for the urine, here is collected and stored before disposal. After the urinary bladder, the urine goes through the urethra, which is a tube, to exit the body.

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Who is alexander hamilton?
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Answer:

He was an American statesman, politician, legal scholar. military commander, lawyer, banker and economist.

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2 years ago
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Zinc phosphide, Zn3P2, is often used as a rat poison. Phosphorus has 5 valence electrons. How many valence electrons does each z
Helen [10]
The choices that should have accompanied this question were:
A. 1 
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4 
</span>
My answer is B. 2.
Below is an explanation, I found while doing the research.

<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.

Phosphate wants to imitate the electron configuration of Argon because noble configurations are the most stable. With P getting the extra electrons the valence shell will be 3s2 3p6, which is the same as Argon. Without the extra electrons, the P valence shell looks like this 3s2 3p3, now you can see why each phosphorus wants 3 more electrons, that will make it 3s2 3p6, just like Argon.</span>
8 0
3 years ago
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Calculate the grams of nitrogen in 125 g of NH4NO3
Marta_Voda [28]

Answer:

43.75 g of Nitrogen

Explanation:

We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:

Mole of NH₄NO₃ = 1 mole

Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)

= 14 + 4 + 14 + 48

= 80 g/mol

Mass of NH₄NO₃ =?

Mass = mole × molar mass

Mass of NH₄NO₃ = 1 × 80 = 80 g

Next, we shall determine the mass of N in 1 mole of NH₄NO₃.

Mass of N in NH₄NO₃ = 2N

= 2 × 14

= 28 g

Thus,

80 g of NH₄NO₃ contains 28 g of N.

Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:

80 g of NH₄NO₃ contains 28 g of N.

Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.

Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen

5 0
2 years ago
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