Question

Michelle is trying to find the average atomic mass of a sample of an unknown

Answer 1

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

• Abundance of isotope A (A%) = 59.34%
• Mass of isotope A = 113.6459 amu
• Mass of isotope B = 115.8488 amu
• Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
• Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

$Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu$

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336