If measurements are all consistent, such as 3.4, 3.6, 3.5, these numbers are said to have

docker41 [41]

buffers resist changes in pH levels, they are used to regulate biological functions that only occur at certain pH levels.

8 0

3 years ago

Read 2 more answers

Which type of fertilization and development is exhibited by birds and many reptiles?

MaRussiya [10]

Answer: Internal fertilization

Explanation: Most birds and reptiles undergoes internal fertilization in which the sperm cells are ejected and fertilizes the egg cell inside the body of the animal.

4 0

4 years ago

Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10

PtichkaEL [24]

Answer:

$K.E.=1.97\times 10^{-21}\ J$

Explanation:

Given that:-

Pressure = $6.9\times 10^5\ Pa$

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

Given the value of pressure = 43,836 Pa

So,

$6.9\times 10^5\ Pa$ = $\frac{6.9\times 10^5}{101325}$ atm

Pressure = 6.80977 atm

Volume = $2.3\times 10^{-3}\ m^3$ = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

So, $K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J$

$K.E.=1.97\times 10^{-21}\ J$

3 0

3 years ago

0.010 moles of carbon C4H10 reacts with oxygon as in the queation 1.76g of carbon dioxide and 0.90 of water are produced. Use th

Sonbull [250]

The coefficients are 2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

Step 1. Gather all the information in one place.

M_r: 58.12 32.00 44.01 18.02

aC₄H₁₀ + bO₂ ⟶ cCO₂ + dH₂O

m/g: 1.76 0.90

n/mol: 0.010

Step 2. Calculate the mass of C₄H₁₀.

Mass = 0.010 mol C₄H₁₀ × (58.12 g C₄H₁₀/1 mol C₄H₁₀) = 0.581 g C₄H₁₀

Step 3. Calculate the mass of O₂

Mass of C₄H₁₀ + mass of O₂ = mass of CO₂ + mass of H₂O

0.581 g + x g = 1.76 g + 0.90 g

x = 1.76 + 0.90 - 0.581 = 2.079

Our information now has the form:

M_r: 58.12 32.00 44.01 18.02

aC₄H₁₀ + bO₂ ⟶ cCO₂ + dH₂O

m/g: 0.581 2.079 1.76 0.90

n/mol: 0.010

Step 4. Calculate the moles of each compound.

Moles of O₂ = 2.079 g O₂ × (1 mol O₂/32.00 g O₂) = 0.064 97 mol O₂

Moles of CO₂ = 1.76 g CO₂ × (1 mol CO₂/44.01 g CO₂) = 0.040 00 mol CO₂

Moles of H₂O = 0.90 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.0499 mol H₂O

Our information now has the form:

aC₄H₁₀ + bO₂ ⟶ cCO₂ + dH₂O

n/mol: 0.010 0.064 97 0.040 00 0.0499

Step 5: Calculate the molar ratios of all the compounds.

a:b:c:d = 0.010:0.064 97:0.040 00:0.0499 = 1:6.497:4.000:4.99

= 2 :12.99:8.00:9.98 ≈ 2:13:8:10

∴ a = 2; b = 13; c = 8; d = 10

The balanced equation is

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

7 0

3 years ago

4. Describe how you will measure the volume of a piece of stone

mariarad [96]

Answer:

One way to measure the volume of any irregular object (in your case, a stone) is to submerge it completely under water and measure the change in the height of the water level. This change in the water level (let's say it goes from 50 mL to 65 mL) indicates that the stone has a volume of 15 mL.

3 0

3 years ago