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MariettaO [177]
4 years ago
13

Which type of fertilization and development is exhibited by birds and many reptiles?​

Chemistry
1 answer:
MaRussiya [10]4 years ago
4 0

Answer: Internal fertilization

Explanation: Most birds and reptiles undergoes internal fertilization in which the sperm cells are ejected and fertilizes the egg cell inside the body of the animal.

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Determine the theoretical yield of P2O5, when 3.07 g of P reacts with 6.09 g of oxygen in the following chemical equation
saveliy_v [14]

Answer: 14.2 grams

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of phosphorous (P) = 3.07 g

Molar mass of phosphorous (P) =  31 g/mol

Putting in the values we get:

\text{Number of moles of phosphorous}=\frac{3.07g}{31g/mol}=0.1moles

given mass of oxygen O_2 = 6.09 g

Molar mass of oxygen O_2 =  32 g/mol

Putting in the values we get:

\text{Number of moles of oxygen}=\frac{6.09g}{32g/mol}=0.2moles

According to stoichiometry:

4P+5O_2\rightarrow 2P_2O_5

4 moles of phosphorous combine with 5 moles of oxygen

Thus 0.1 moles of phosphorous combine with =\frac{5}{4}\times 0.1=0.125 moles of oxygen

Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.

4 moles of phosphorous gives=  2 moles of P_2O_5

Thus 0.1 moles of phosphorous gives =\frac{2}{4}\times 0.1=0.05 moles of P_2O_5

mass of P_2O_5=moles\times {\text {Molar mass}}=0.05\times 284=14.2g

Thus the theoretical yield of P_2O_5 is 14.2 grams.

5 0
3 years ago
PLEASE ASNER
Rina8888 [55]

Answer:

London dispersion forces

Explanation:

The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.

4 0
3 years ago
When a polar molecule causes a charge redistribution in a nonpolar molecule, what are the molecules of the mixture most likely e
White raven [17]

Answer is: dipole-induced dipole interactions.

Intermolecular forces are the forces between molecules or particles.

There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces and van der Waals forces.

A dipole-induced dipole interaction is a weak attraction that results when a polar molecule induces a dipole in a nonpolar molecule by disturbing the arrangement of electrons in the nonpolar species.

4 0
3 years ago
Read 2 more answers
1. Determine whether or not the equation below is balanced. If it isn’t balanced, write the balanced form. Also, identify the re
strojnjashka [21]

Answer:

- Not balanced.

- Reactants: Zn  and HCI .

- Products: ZnCl₂ and  H₂.

- Substitution reaction.

Explanation:

Hello,

In this case, for the given reaction:

Zn  +  HCI  →  ZnCl₂ +  H₂

We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:

Zn  +  2HCI  →  ZnCl₂ +  H₂

And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:

Reactants: Zn  and HCI .

Products: ZnCl₂ and  H₂.

Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.

Best regards.

5 0
4 years ago
What is the limiting reactant when 19.9 g CuO react with 2.02 g H2?
Harlamova29_29 [7]

Answer:

Explanation:

use the equation

moles = mass/mr

=19.9/79.5

=0.250moles of CuO

then do the same for

H = 2.02/1

=2.02

so CuO is the limiting reagent because there is less amount of it.

Hope this helps  :)

4 0
3 years ago
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