In one meter, there is 10000 milimeters. Just multiply however many meters you have by 10000, and youll have your answer.
~Silver
Answer:
+2
Explanation:
Because an electron has a negative charge.
The reaction equilibrium is:
ClO⁻ + H₂O ⇄ HClO + OH⁻
Keq =
![\frac{[HClO][OH^{-} ]}{[ClO^{-} ]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BHClO%5D%5BOH%5E%7B-%7D%20%5D%7D%7B%5BClO%5E%7B-%7D%20%5D%7D%20)
Answer:
5SiO2 + 2CaC2 --> 5Si + 2CaO + 4CO2
4NH3 + 5O2 --> 4NO + 6H2O
Answer:
20.95 g of caffeine, C₈H₁₀N₄O₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules of C₈H₁₀N₄O₂ = 6.5×10²² molecules
Mass of C₈H₁₀N₄O₂ =?
From Avogadro's hypothesis,
1 mole of C₈H₁₀N₄O₂ = 6.02×10²³ molecules
Next, we shall determine the mass of 1 mole of C₈H₁₀N₄O₂. This can be obtained as follow:
1 mole of C₈H₁₀N₄O₂ = (8×12) + (10×1) + (4×14) + (2×16)
= 96 + 10 + 56 + 32
1 mole of C₈H₁₀N₄O₂ = 194 g
Thus,
194 g of C₈H₁₀N₄O₂ = 6.02×10²³ molecules
Finally, we shall determine the mass of caffeine, C₈H₁₀N₄O₂ that contains 6.5×10²² molecules. This can be obtained as follow:
6.02×10²³ molecules = 194 g of C₈H₁₀N₄O₂
Therefore,
6.5×10²² molecules = (6.5×10²² × 194) / 6.02×10²³
6.5×10²² molecules = 20.95 g of C₈H₁₀N₄O₂.
Therefore, 20.95 g of caffeine, C₈H₁₀N₄O₂ contains 6.5×10²² molecules
