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lesya [120]
3 years ago
11

PLZ HELP ME IM FAILING! Everything you need to know about the question is on the photo

Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

C. NH₄Cl

Explanation:

The compound with the element ratio 1 : 4 : 1 from the given choices is NH₄Cl.

An element is a pure substance made up of distinct number of atoms. Elements are unique and are different from other elements because of the nature of their atoms.

We often delineate an element using chemical symbols.

   In the compound NH₄Cl;

There are 3 elements:

           Number of atoms

N                      1

H                      4

Cl                     1

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Answer:

Hope this helps! (;_;)/

Explanation:

3 0
3 years ago
A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Us
drek231 [11]

Answer:6.0M

Explanation:see attached photo

3 0
4 years ago
Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

6 0
2 years ago
Who goes to K12 and if so what grade
olchik [2.2K]

Answer:

I might next year with my cuz and nex year ima be in 8th

Explanation:

8 0
3 years ago
Read 2 more answers
The process of energy being captured
Amanda [17]

Answer:

B

Explanation:

I am not sure but I think it is B. Out of all the answers that one makes sense.

5 0
3 years ago
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