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yawa3891 [41]
3 years ago
7

Two straight roads diverge at an angle of 45°. Two cars leave the intersection at 2:00 P.M., one traveling at 32 mi/h and the ot

her at 54 mi/h. How far apart are the cars at 2:30 P.M.? (Round your answer to two decimal places.)
Physics
1 answer:
svp [43]3 years ago
3 0

Answer:19.34 miles

Explanation:

Given

First car travels with 32 mi/h

second travels with 54 mi/h

they leave at 2:00 Pm at 45

distance traveled by them is 0.5 hr

suppose First is traveling towards x axis and another travels 45 to it

Distance traveled by first car is 32\times 0.5=16 miles

Position vector of first car after 0.5 hr

\vec{r_1}=32\times 0.5(\cos (45)\hat{i})

Position vector of second car after 0.5 hr

\vec{r_2}=54\times 0.5(\cos (45)\hat{i}+\sin (45)\hat{j})

distance between them

\vec{r_{21}}=27(\cos (45)\hat{i}+\sin (45)\hat{j})-16(\cos (45)\hat{i})

\vec{r_{21}}=3.09\hat{i}+27\hat{j}\sin (45)

distance between them|\vec{r_{21}}|=19.34

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6 0
3 years ago
a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?
Liono4ka [1.6K]

<u>Answer:</u>

The acceleration of the car is 3.13 m/s^2

<u>Explanation:</u>

In the question it is given that car initially heads north with a velocity 15 m/s. It then accelerates for 4.25 s and in the end its velocity is 28.3 m/s.

initial velocity u = 15 m/s

time t=4.25 s

final velocity v=28.3 m/s

The equation of acceleration is

a= \frac{(v-u)}{t}

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2 years ago
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Answer:

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Explanation:

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Number of blocks traveled by bus towards north = 8

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