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Alika [10]
1 year ago
5

The weight of an object ____.

Chemistry
1 answer:
miv72 [106K]1 year ago
3 0

Explanation:

the. correct option is d

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What is a “ medium” in regards to waves ?
raketka [301]
A medium can be anything that a wave can pass through e.g the medium can be solid objects, air, water, etc.
3 0
2 years ago
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Which substance is the oxidizing agent in the following reaction? Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Which substance
aleksandr82 [10.1K]

Answer:

HNO3 is the oxidizing agent

Explanation:

Step 1:

The oxidizing agent is responsible to oxidize another.  but  itself undergoes  a reduction  .

Fe2S3:

Fe has an oxidation number of +3

S has an oxidation number of -2

HNO3:

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

H has an oxidation number of +1

N has an oxidation number of +5

Fe(NO3)3

O has an oxidation number of -2 ( we have 3 times O so this makes -6)

Fe has an oxidation number of +3

Since NO3 has an oxidation number of -1; N has an oxidation number of +5

S alone has an oxidation number of 0

NO2:

O has an oxidation number of -2 (we have 2 times O, this makes -4)

N has an oxidation number of +4

Fe doesn't change from oxidation number. It stays +3

N goes from +5 to +4 → this is a reduction

S goes from -2 to 0 → this is an oxidation

The reducing agent is the compound that contributes the oxidized species (S).

The oxidizing agent contributes the reducing species (N)

The answer is HNO3

5 0
3 years ago
Choose the correct name for each acid. Click here
Zigmanuir [339]

Answer:

1. Nitrous Acid

2. Hydroiodic Acid

3. Phosphoric Acid

Explanation:

Just did the lesson

7 0
3 years ago
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If i increase the [h+] of a solution by 10x, how much will the ph change? and in what direction will ph change?
igomit [66]
For example...
You have solution with [H+] = 0,01M
>>>> pH = -log[H+] = -log0,01 = 2

And you increase the [H+] by 10x ---> 0,01×10 = 0,1M
>>>> pH = -log0,1 = 1

○ pH decrease by 2x
○ pH is more acidic
4 0
3 years ago
Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how
Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )


3 mol                10 mol


C_{3}H_{8} is /excess /reactant

because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

Only 2 mole propane will be burned,

so 

2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off

Correct answer is number 4.



5 0
2 years ago
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