A mover hoists a 50 kg box from the ground to a height of 2 m. What was the change in the box's energy

Physics

1 answer:

SSSSS [86.1K]3 years ago

3 0

Answer:

980 J

Explanation:

The change in box's energy is equal to its change in gravitational potential energy:

$\Delta U = m g \Delta h$

where

m = 50 kg is the mass of the box

g = 9.8 m/s^2 is the acceleration due to gravity

$\Delta h= 2m$ is the change in height of the box

Substituting numbers, we find

$\Delta U = (50 kg)(9.8 m/s^2)(2 m)=980 J$

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A car transports its passengers between 3 buildings. It moves from the first building to the second building, 4.76km away, in a

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Answer:

1) a = 6.14 km

2) b = 4.69 km

Explanation:

Let the first building be A, second building be B and third building be C.

Now, bearing of A = 4.76 km in a direction 37° north of east

Bearing of B = 69° west of north

Bearing of C = 28° east of south

Thus if this 3 points form a triangle, we will have the following angles;

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Angle at point C = 180 - (81 + 49) = 50°

Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;

Using sine rule, we can find "a".

a/sin 81 = 4.76/sin 50

a = 6.14 km

B) distance between first and third building is AB in the triangle depicted by "b".

Similar to the first problem, we will use sine rule again.

b/sin49 = 4.76/sin 50

b = 4.69 km