Answer:
1946 ft
Explanation:
The distance is the addition of the distance gotten from both triangles.
d = x + y
d = 1178 ft + 768 ft
d = 1946 ft
Attached is a picture showing how I arrived at the answer
Answer:
7.35m/s²
Explanation:
From the question we are not told what to find but we can as well find the acceleration of the wagon.
According to newton second law of motion

Fm is the moving force = 410N
is the coefficient of friction = 0.18
m is the mass = 45kg
g is the acceleration dur to gravity = 9.8m/s²
a is the acceleration of the wagon
Substitute the given data into the equation ang get ax

Hence the acceleration of the wagon is 7.35m/s²
Answer:
M₂ = M then L₂ = L
M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive
∑ τ = 0
The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂
The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.
M L + M₁ 0 - m₂ L₂ = 0
M L - m₂ L₂ = 0
L₂ =
L
From this answer we have several possibilities
* if the two masses are equal then L₂ = L
* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L
Complete question
The complete question is shown on the first uploaded image
Answer:
The velocity is 
Explanation:
From the question we are told that
a = nb
The length of the minor axis of the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the Empire's symbol, (an ellipse)
Now this length seen by the observer can be mathematically represented as

Here t is the actual length of the major axis of of the Empire's symbol, (an ellipse)
So t = a = nb
and b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the Empire's symbol, (an ellipse)
i.e h = b
So
![[\frac{1}{n} ]^2 = 1 - \frac{v^2}{c^2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bn%7D%20%5D%5E2%20%3D%20%201%20-%20%20%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D)
![v^2 =c^2 [1- \frac{1}{n^2} ]](https://tex.z-dn.net/?f=v%5E2%20%3Dc%5E2%20%5B1-%20%5Cfrac%7B1%7D%7Bn%5E2%7D%20%5D)
![v^2 =c^2 [\frac{n^2 -1}{n^2} ]](https://tex.z-dn.net/?f=v%5E2%20%3Dc%5E2%20%5B%5Cfrac%7Bn%5E2%20-1%7D%7Bn%5E2%7D%20%5D)

Since we have 15 kilometers per hour, and we're looking for 20 minutes, let's set up proportions.
20/60 minutes = x/15
20/60 = 1/3, so let's leave that simplified.
1/3 = x/15
Look at the denominators, 3 to 15 is a factor of 5, so multiply the numerator by 5.
1 • 5 = 5, so you will cover 5 kilometers in 20 minutes.
I hope this helps!