The final speed when the mass is 40,000kg height is 2.5km and 500,000N of force is 176.8 m / s
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
a = Acceleration
m = 40000 kg
F = 500000 N
a = F / m
a = 500000 / 40000
a = 12.5 m / s²
a = v / t
v = d / t
v = Velocity
t = Time
d = Distance
d = 2.5 km = 2500 m
a = d / t²
12.5 = 2500 / t²
t² = 200
t = 14.14 s
v = 2500 / 14.14
v = 176.8 m / s
Therefore, the final speed is 176.8 m / s
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Answer:
Ari catches up to Amanda at 19.3 meters
Explanation:
We have given Ari is swimming a 25-meter race.
It is given that after swimming 6 meters she catches up to Amanda in a ratio of 7:3 from the 6-meter mark.
So ,The distance between 6 meters and 25 meters = 25-6 =19 meters
It is given that she catched Amanda in ratio 7:3
So, she catched her at
of the distance
So, the distance at which she catched Amanda ![\frac{7}{10}\times 19=13.33meter](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B10%7D%5Ctimes%2019%3D13.33meter)
Ari catches 13.3 metres from 6 m marks
So the total distance = 13.33+6 =19.33 meters
So Ari catches up to Amanda at a distance of 19.33 meters
Answer:
The current will be 3.23 A.
Explanation:
Given that,
Current I = 4.68 A
Voltage V = 220 volt
We need to calculate the resistance
Using ohm's law
![V = I R](https://tex.z-dn.net/?f=V%20%3D%20I%20R)
![R = \dfrac{V}{I}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7BV%7D%7BI%7D)
Where,
V = voltage
I = current
R = resistance
Put the value into the formula
![R = \dfrac{220}{4.68}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7B220%7D%7B4.68%7D)
![R = 47\ \Omega](https://tex.z-dn.net/?f=R%20%3D%2047%5C%20%5COmega)
We need to calculate the current
If the voltage drops by 31%
Voltage will be
![V'=V-V\times31%](https://tex.z-dn.net/?f=V%27%3DV-V%5Ctimes31%25)
![V'=220-220\times\dfrac{31}{100}](https://tex.z-dn.net/?f=V%27%3D220-220%5Ctimes%5Cdfrac%7B31%7D%7B100%7D)
![V'=151.8\ volt](https://tex.z-dn.net/?f=V%27%3D151.8%5C%20volt)
Now, the current will be
![I = \dfrac{151.8}{47}](https://tex.z-dn.net/?f=I%20%3D%20%5Cdfrac%7B151.8%7D%7B47%7D)
![I=3.23\ A](https://tex.z-dn.net/?f=I%3D3.23%5C%20A)
Hence, The current will be 3.23 A.
Answer:
During heat flow, much of the energy is dissipated and cannot be used for useful work.
Explanation:
Which of the following statements is true?
During heat flow, much of the energy is lost.
During heat flow, energy is converted to matter.
During heat flow, much of the energy is dissipated and cannot be used for useful work.
Erosion over thousands of millennia from the stream or river in the valley