How do I find the average number of particles hitting the surface poer unit area and per unit time with no information?
Answer: A_a^3
B_c^1
Step-by-step explanation:they work like integers therefore vlby sharing the same base and Having the division sign u just subtract the powers
Answer:
10560 feet
Step-by-step explanation:
multiply the length value by 5280
Answer:
97
Step-by-step explanation:
Given that:
Low = 43bpm
High = 115 bpm
Error = 3
α = 90%
To find the range estimate :
Standard destviation = (high - low) / 4
Standard deviation = (115 - 43) / 4
Standard deviation = 72/4 = 18
The sample size,(n) :
n = [(Zα/2 * sd)/E] ²
2 - tail = (Zα/2) = 1.645
[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²
= 97.41
Sample size = 97
Hey there! I'm happy to help!
Let's call the length and width L and W respectively.
L=2W+8
2W+2L=124
We plug our value of L into the second equation and solve for W.
2W+2(2W+8)=124
We undo the parentheses with the distributive property.
2W+4W+16=124
Combine like terms.
6W+16=124
Subtract 16 from both sides.
6W=108
Divide both sides by 6.
W=18
We plug this W value into the first equation to solve for L.
L=2(18)+8
L=36+8
L=44
So, the length is 44 feet and the width is 18 feet.
Have a wonderful day! :D
