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Lina20 [59]
3 years ago
7

How much taxes will I pay on 45.000 per year claiming myself

Mathematics
2 answers:
lina2011 [118]3 years ago
8 0
99$ Because you are broke and can’t afford the real amount of taxes and want to save the rest of your money for the strip club
creativ13 [48]3 years ago
6 0
Well, it depends. In different states or even counties, you could be taxed much differently. If there are options though for your question, then I could answer. Hope this helps! GBY! :)
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Eight times what equals 226
PSYCHO15rus [73]

Answer:

28.25

Step-by-step explanation:

just do 226 divided by 8

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Maria put 18 crayons in 3 different baskets. She put the same number of crayons in each basket. How many crayons did Maria put i
allochka39001 [22]
54 i believe

explanation: if you put 18 crayons in 3 baskets each it’s gotta b 54
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Rule add 15, subtract 10 first term4
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I think that would be 9 I am not sure.

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Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
Need help!
siniylev [52]

<u>Correct </u><u>Inputs </u><u>:-</u>

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrow Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

\leadstoMedian is the line segment from a vertex to the midpoint of the opposite side.

<u>Let us Check all options one by one </u>

  • CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

  • BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

  • AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

  • AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

  • AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️
8 0
2 years ago
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