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abruzzese [7]
3 years ago
8

Plz help on last question i asked

Chemistry
2 answers:
maxonik [38]3 years ago
8 0

Answer:

The total energy but the photons will give is 6.615 x 10^-14

Explanation:

klasskru [66]3 years ago
5 0

Answer:

The total energy but the photons will give is 6.615 x 10^-14

Explanation:

Formula that can be used in this question is E= hf or E= hc/ λ

This is the formula that can be used to calculate the energy that the photon is carrying where it is given as the Planck's Constant .

Now putting the values given in the equation that can calculate energy we get Planck's Constant is equal to 6.62 x 10^-34

E=(6.62 x 10^-34 x 2.998 x 10^8) / ( 3 x 10^-12 )

E=6.615 x 10^-14

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I WILL MAKE U THE BRAINLIEST !!
bogdanovich [222]

Answer:

Try using Ptable or chemicalaid

Explanation:

Ptable is a great website that shows you a dynamic periodic table. It can show you which elements are Halogens, Alkali metals, transition metals, noble gases, and etc!

Chemicalaid is a nice website to find out more information about specific elements, it also lists every element on the periodic table.

5 0
3 years ago
Is Salt and pepper an example of a homogenous mixture?
alisha [4.7K]

Answer:

no it is a heterogeneous mixture because salt and pepper are not mixed uniformly.

4 0
4 years ago
Why is it important for scientists to use the scientific method?
shtirl [24]
I believe the answer is A
3 0
3 years ago
The combustion of caffeine with the molecular masses is given below. If you have 0.150 grams of caffeine, how much NO2 in grams
lord [1]

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

8 0
3 years ago
You have at your disposal 3 1-pound bags of various pure salts that dissolve readily in water. You can add one of the bags to a
Sedaia [141]

Answer:

This question appears incomplete

Explanation:

However, it should be noted that addition of soluble salts generally lowers the freezing point of water hence after the addition, water will no longer freeze at 0°C but lower.

Soluble salts tend to form more ions in water, it is these ions that are responsible for interfering with the hydrogen bonds hence lowering the freezing. Thus, (since each bag are of the same weight) <u>the bag that contains the salt that ionizes more in water will lower the freezing point by the greatest amount</u>.

NOTE: Different weight of the salts could lead to more ions been formed in the water by some salts as against the other.

6 0
4 years ago
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