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yanalaym [24]
3 years ago
7

explain why the reaction between lead (II) nitrate and concentrated sulphuric (VI) acid starts and stops immediately?​

Chemistry
1 answer:
Mariana [72]3 years ago
7 0

Answer:

The reaction produces insoluble lead (II) sulphate which coats the surface of lead (II) nitrate  [Pb(NO3)]

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An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
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Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

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Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

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