(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =
</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
They just are very cute tho and cute and funny and
I honestly have no clue on this one
Answer:
C. 0.72 M
Explanation:
To calculate the molarity use the following equation, C=n/V
You have the molar number n which is 0.702 and the volume 0.98 L
Replace those numbers in the formula C=0.702/0.98= 0.72 M
Answer:
See Explanation
Explanation:
Note => 1st one should understand that for an 'acid' to be an acid and a 'base' to be a base, two requirements must be met, (1) the compound must have an ionizable Hydrogen for acids or Hydroxide for bases, and (2) must be in water and ionize delivering H⁺ ions from acids and OH⁻ ions from bases. The Arrhenius acids are characterized by having an ionizable hydrogen which when added into water increases the hydronium ion concentration (H₃O⁺). Arrhenius bases are characterized by having an ionizable hydroxide function (OH-).
Typically, the acids and bases are characterized as either strong or weak electrolytes. the Strong electrolytes ionize 100% in water and Weak electrolytes less than 100%.
The strong acids include HCl, HBr, HI, HNO₃, HClO₄ and H₂SO₄ (1st ionization step). Any acid (H-Anion) not a member of the strong 6 is a weak acid.
The strong Arrhenius Bases are Group IA and Group IIA Hydroxides except for Beryllium Hydroxide. Weak Arrhenius Bases are ammonia or ammonia derivatives (amines) in water.
=> NH₃ + H₂O => NH₄OH ⇄ NH⁺ + OH⁻.
The ammonia derivatives follow the same reactive nature in water.
=> RNH₂ + H₂O => RNH₃OH ⇄ RNH₃⁺ + OH⁻ where R- is a structural substrate; e.g., Methyl Amine => H₃C - NH₂ .
