How many electrons does an ion of magnesium have if it’s represented by the symbol shown below? 25Mg2+
1 answer:
Answer:
10 electrons.
Explanation:
Hello!
In this case, since a normal atom of magnesium has 12 protons and electrons when is not in the form of a cation, since it is a metal that tends to lose electrons when ionized, and therefore it becomes positively charged, we infer that in form of:
It only has 10 electrons.
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Answer:
1,812 wt%
Explanation:
The reactions for this titration are:
2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻
I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻
The moles in the end point of S₂O₃⁻ are:
0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:
4,463x10⁻⁴ moles of S₂O₃⁻× = 2,2315x10⁻⁴ moles of I₃⁻
As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:
2,2315x10⁻⁴ moles of I₃⁻× = 4,463x10⁻⁴ moles of Ce(IV). These moles are:
4,463x10⁻⁴ moles of Ce(IV)× = <em>0,0625 g of Ce(IV)</em>
As the sample has a 3,452g, the weight percent is:
0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>
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Answer:
A buffer solution is prepared by adding 13.74 g of sodium acetate (NaC2H3O2) and 15.36 g of acetic acid to enough water to make 500 mL of solution.
Calculate the pH of this buffer.
Explanation:
The pH of a buffer solution can be calculated by using the Henderson-Hesselbalch equation:
The pH of the given buffer solution can be calculated as shown below:
Answer:
= -4.2°C
= 49.4°C
Explanation:
A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:
|| =
Similarly,
|| = |
| + |
|
During winter, the value of || = 20°C = 273.15 + 20 = 293.15 K and |
| = 1.5 kW. Therefore,
|| = 0.75(
-
)
Similarly,
|| = 1 -
1.5/0.75*(293.15-) = 1 - (
/293.15
Further simplification,
= -4.2°C
During summer, = 25°C = 273.15+25 = 298.15 K, and |
| = 1.5 kW. Therefore,
|| = 0.75(
-
)
Similarly,
|| =
- 1
1.5/0.75*( - 298.15) = (
/298.15
Further simplification,
= 49.4°C