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2 years ago

Consider the densities of the

Chemistry

1 answer:

serious [3.7K]2 years ago

6 0

The Percent error in the calculation of densities of the metal during experiment is 0.03 %

<h3>What is Percentage error?</h3>

Percent error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage.

Percent error = [Experimental value - Theoretical value] / Theoretical value x 100%

Percent error = 7.83 -7.86 / 7.86 x 100

= 0.03 %

Learn more about percentage error here ;

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What is the angle between the carbon-sulfur bonds in the carbon disulfide ( cs2 ) molecule?

Bingel [31]

Answer:

180º

Explanation:

Carbon has 4 valence electrons and to complete the octet requires 4 more , so it will share with the oxigen atoms 4 more, forming a single and a pi bond similar to CO2

Since the carbon does not have lone pairs, the geometry around this central atom will be linear and the angle will be 180 , S = C = S

7 0

3 years ago

An empty beaker weighs 39.09 g

Vinvika [58]

<span>To work out the volume of something from its density, use the compound measures triangle: mass over density and volume. To find volume that the beaker holds, divide the mass by the density. V = (388.15 - 39.09)/1. V = 349.06g/cm3. To find the weight of the beaker and the contents, first work out the weight (mass) of the mercury, with this formula: mass = d x v. M = 13.5 x 349.06. M = 4712.31. Then add on the weight of the beaker (39.09g). The total weight is 4751.40g.</span>

3 0

3 years ago

1. Which phase change is accompanied by the release of heat? A) H20(s)--> H2O(g) B) H20(l) ->H2O(s) C) H20(l)→ H2O(g) D) H

docker41 [41]

Answer:

B, liquid to solid.

Explanation: Since heat is being released, the particles for H2O would clump up. Heat is basically being taken out.

5 0

3 years ago

If you want 370 mL of 2.3 M AgNO3 solution, how many grams of AgNO3 do you need?

Allisa [31]

dont use that link its bad

8 0

3 years ago

Metal rings can be coated with a layer of copper using electricity.

Eduardwww [97]

<u>First of all, what is electrolysis?</u>

Electrolysis is the process of breaking down ionic substances using direct current.

<u>Important points about electrolysis </u>

→ Ionic substances contain particles called ions.

→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.

→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.

→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.

<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>

Metal ions form at the cathode and non-metal ions form at the anode

How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG

OIL = Oxidation is Loss (of electrons)

RIG = Reduction is Gain (of electrons)

<h2><em><u>The answer to your question</u></em></h2>

1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.

2) You want to put the solution you are given in to the tank your going to be using.

3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).

4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.

5) Then a thin layer should form on the electrode.

Hope this helps :)

5 0

3 years ago