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2 years ago

Consider the densities of the

Chemistry

1 answer:

serious [3.7K]2 years ago

6 0

The Percent error in the calculation of densities of the metal during experiment is 0.03 %

<h3>What is Percentage error?</h3>

Percent error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage.

Percent error = [Experimental value - Theoretical value] / Theoretical value x 100%

Percent error = 7.83 -7.86 / 7.86 x 100

= 0.03 %

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Are inner planets rockier or more like gas??

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Inner planets are rockier and outer planets are gaseous. Hope this helps! Can I have brainliest please

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3 years ago

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You are measuring how many liters of oxygen are in a container. which of the following are you measuring?

svetoff [14.1K]

Answer:

Explanation:

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3 years ago

Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen react with 70. 0 g of

harkovskaia [24]

In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

The reaction is the following:

3H₂(g) + N₂(g) → 2NH₃(g) (1)

To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

$n = \frac{m}{M}$

Where:

m: is the mass

M: is the molar mass

For hydrogen we have:

$n_{H_{2}} = \frac{m}{M} = \frac{7.00 g}{2.016 g/mol} = 3.47 \:moles$

And for nitrogen:

$n_{N_{2}} = \frac{m}{M} = \frac{70.0 g}{28.013 g/mol} = 2.50 \:moles$

We can see in reaction (1) that 3 moles of hydrogen react with 1 mol of nitrogen, so the number of hydrogen moles needed to react nitrogen is:

$n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles$

Since we have 3.47 moles of hydrogen and we need 7.50 moles to react with all the mass of nitrogen, the limiting reactant is hydrogen.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that 3 moles of hydrogen produces 2 moles of ammonia, so:

$n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles$

Hence, hydrogen would produce 2.31 moles of ammonia.

Therefore, hydrogen is the limiting reactant because 7.5 moles of hydrogen would be needed to consume the available nitrogen (option 1).

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3 years ago

How many grams of drug powder would you need to weigh to prepare 32ml of a suspension that should have a strength of 20mg/ml?

butalik [34]

15 grams for the drug powder

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27. Which of the following molecules are chiral?(EXTRA CREDIT I. 2-Chlorobutane II. 3-Bromopentane ?. 1-Bromo-2-methylpropene IV

igor_vitrenko [27]

2-Chlorobutane, 2-Bromo-3-methylbutane are chiral .

chiral condition - a compound is said to be chiral if it is surrounded by 4 different groups

I,IV are chiral

II,III are achiral

Molecular types with non-superposable mirror images are known as chiral molecules. The existence of an asymmetric carbon atom in a molecule is the characteristic that most frequently contributes to chirality. When referring to an object that cannot be superposed on its mirror counterpart, the adjective "chiral" is generally employed.

A corkscrew, golf clubs, scissors, and other chiral items all have a "handedness." Thus, one can get scissors and golf clubs that are designed for either hand. Gloves and shoes are also sold in pairs, a right and a left.

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1 year ago