Answer:
pH ( potential Hydrogen ) is a negative logarithm of molar concentration of hydrogen ions.
![pH = - log[H {}^{ + } ]](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20log%5BH%20%7B%7D%5E%7B%20%2B%20%7D%20%5D)
therefore:
A covalent compound is formed when a chemical reaction occurs between atoms of separate molecules
C(Molarity) = n of solute/V of solution (mol/L)
glucose(C6H12O6) = 180g/mol
glucose 35g = 35g/(180g/mol) = 0.1944mol
We need density of solution here, and I assume it as density of phenol, 1.07g/mL. (I don't know why the question doesn't contain it)
phenol 0.16kg = 0.16kg/(1.07kg/L) = 0.1495L
0.1944mol/0.1495L = 1.300M(mol/L)
Answer:
The gold foil experiment
El experimento de la lámina de oro
Explanation:
Answer:
a) E = 0.477 V
b) E = 0.502 V
c) 0.02 M = [Ni+2]
d)[Zn+2] = 1.81 M
Explanation:
having the following reactions of each cell:
Zn =⇒ Zn+2 + 2e- +0.76
Ni+2 + 2e- =⇒ Ni -0.25
Zn + Ni+2 ==⇒ Ni + Zn+2 Eo = 0.51
a)
The number of electrons being transferred is 2, therefore n = 2 in the Nernst equation
E = Eo - 0.0592/2*log [Zn+2]/[Ni+2] = 0.51 - 0.0592/2*log[0.13/1.7] = 0.477 V
b)
using the formula above:
E = 0.51 - 0.0296*log [Zn+2]/[Ni+2] = 0.51 - 0.0296*log((0.13+0.5)/(1.7-0.5)) = 0.502 V
c)
using the formula above:
0.45 = 0.51 - 0.0296*log[Zn+2]/[Ni+2]
-0.06/-0.0296 = log[Zn+2]/[Ni+2]
2.02 = log [Zn+] / [Ni+2]
104.71 = [Zn+2] / [Ni+2]
x = change in [Ni+2]
[Ni+2] = 1.70 - x
[Zn+2] = 0.13 + x
0.13 + x/1.70 –x = 104.71
Resolving x:
x = 1.68 M
[Ni+2] = 1.70 - 1.68 = 0.02 M
d)
[Zn+2] = 0.13 + x = 0.13 + 1.68 = 1.81 M
