Nojzjxjsjs dsndjdjdjneksjsns

Why does chlorine react vigorously with hydrogen in the presence of sunlight?

AleksandrR [38]

Chlorine react vigorously with hydrogen in the present of sunlight because chlorine has a great attraction for hydrogen's electron. During the reaction, chlorine and hydrogen will donate one electron each from their valence electrons which will be shared equally by both elements, thus forming a covalent bond.

6 0

2 years ago

Be sure to answer all parts.

Llana [10]

Answer:

16 g has 2 sig figs

6701g has 4 sig figs

560 has 2 sig figs

Explanation:

4 0

2 years ago

A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul

yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.

In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

= (47.93 × 417.96 ) ÷ 52.07 %

= 384.729

E₃ = 384.729

Therefore; E = 384.729 ÷ 3

= 128.24

The atomic mass of E is 128.24

6 0

2 years ago

An aqueous KNO3 solution is made using 72.5 g of KNO3 diluted to a total solution volume of 2.00 L. Calculate the molarity, mola

Sonja [21]

Answer:

The molarity is 0.359 $\frac{moles}{L}$

The molality is 0.354 $\frac{moles}{kg}$

The mass percent of the solution es 3.45%

Explanation:

Molarity is a unit of concentration that indicates the amount of moles of solute that appear dissolved in each liter of the mixture. It is determined by:

$Molarity (M)=\frac{number of moles of solute}{volume}$

Being:

K: 39 g/mole
N: 14 g/mole
O: 16 g/mole

The molar mass of KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

You can apply the following rule of three: if 101 grams of KNO₃ are present in 1 mole, 72.5 grams in how many moles are present?

$moles of KNO_{3}=\frac{72.5 grams*1 mole}{101 grams}$

moles of KNO₃= 0.718

So you have:

moles of KNO₃= 0.718
volume= 2 L

Applying this quantity in the definition of molarity:

$molarity=\frac{0.718 moles}{2 L}$

Molarity= 0.359 $\frac{moles}{L}$

The molarity is 0.359 $\frac{moles}{L}$

Molality is a way of measuring the concentration of solute in solvent and indicates the amount of moles of solute in each kilogram of solvent.

Then the molality is calculated by:

$Molality=\frac{moles of solute}{mass of solvent in kilograms}$

Density is defined as the property that matter, whether solid, liquid or gas, has to compress in a given space. That is, it is the amount of mass per unit volume. So, if the density of 1.05 g / mL for the solution indicates that in 1 mL of solution there are 1.05 grams of solution, in 2000 mL (where 2L = 2000 mL, because 1 L = 1000mL) how much mass is there?

$mass=\frac{2000 mL*1.05 grams}{1 mL}$

mass= 2100 grams

Since mass solution = mass water + mass KNO₃

then mass water = mass solution - mass KNO₃

Being mass solution 2100 grams and mass KNO₃ 72.5 grams, and replacing you get: mass water= 2100 grams - 72.5 grams

mass water= 2,027.5 grams

Then, being:

moles of KNO₃= 0.718
mass of solvent in kilograms= 2.0275 kg (being 2,027.5 grams= 2.0275 kilograms because 1,000 grams= 1 kilogram)

Replacing in the definition of molality:

$molality=\frac{0.718 moles}{2.0275 kg}$

molality= 0.354 $\frac{moles}{kg}$

The molality is 0.354 $\frac{moles}{kg}$

The mass percent of a solution is the number of grams of solute per 100 grams of solution. Then the mass percent is the mass of the element or solute divided by the mass of the compound or solute and the result of which is multiplied by 100 to give a percentage.

$mass percent=\frac{mass of solute}{mass of solution} *100$

So, in this case:

$mass percent=\frac{72.5 grams}{2100 grams} *100$

mass percent= 3.45 % KNO₃ by mass

The mass percent of the solution es 3.45%

3 0

2 years ago

A fish is swimming at a constant rate towards the ocean floor. The equation

Natalka [10]

A ﬁsh is swimming at a constant rate toward the ocean ﬂoor. The equation y = −7x − 3 can be used to represent this situation, where y is the depth of the ﬁsh in meters below sea level and x is the number of seconds the ﬁsh has been swimming. Which statement best describes the depth of the ﬁsh, given this equation?
From a starting position of 7 meters below sea level, the ﬁsh is descending 3 meters per second.
B From a starting position of 7 meters below sea level, the ﬁsh is ascending 3 meters per second.
C From a starting position of 3 meters below sea level, the ﬁsh is descending 7 meters per second

7 0

2 years ago