mr oxygen= 16. 16 x 3= 48
mr Al2O3= 27 + 27 + 48= 102
(48/102) X 100%= 47.05% oxygen
Answer
Avogadro's number: One mole of any substance contains 6.022×10²³ molecules
Explanation
While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is
One mole of any substance contains 6.022×10²³ molecules.
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Answer:
0.08 g
Explanation:
100.0 mL = 0.10 L
Multiply the volume by the molarity to find moles.
0.10 L × 0.20 M = 0.002 mol
Convert moles to grams.
0.002 mol × 40 g/mol = 0.08 g
