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VMariaS [17]
3 years ago
12

How would you make up 100 mL of a 0.10 M NaCl solution?

Chemistry
2 answers:
KIM [24]3 years ago
7 0
0.01 moles NaCl into 0.1 Liter solution
aleksley [76]3 years ago
3 0
<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. 

0.10 M = 0.10 mol NaCl / L solution (0.1 L) = 0.01 mol NaCl ( 58.44 g / mol ) = 0.5844 g NaCl needed

Therefore, to prepare the solution, you need to dissolve 0.5844 g of NaCl to 100mL water.</span>
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Phosphorous trichloride (PCl3) is produced
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The percentage yield obtained from the given reaction above is 74.8%

<h3>Balanced equation </h3>

P₄ + 6Cl₂ → 4PCl₃

Molar mass of P₄ = 31 × 4 = 124 g/mol

Mass of P₄ from the balanced equation = 1 × 124 = 124 g

Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol

Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g

<h3>SUMMARY</h3>

From the balanced equation above,

124 g of P₄ reacted to produce 550 g of PCl₃

<h3>How to determine the theoretical yield </h3>

From the balanced equation above,

124 g of P₄ reacted to produce 550 g of PCl₃

Therefore,

79.12 g of P₄ will react to produce = (79.12  × 550) / 124 = 350.9 g of PCl₃

<h3>How to determine the percentage yield </h3>
  • Actual yield of PCl₃ = 262.6 g
  • Theoretical yield of PCl₃ = 350.9 g
  • Percentage yield =?

Percentage yield = (Actual /Theoretical) × 100

Percentage yield = (262.6 / 350.9) × 100

Percentage yield = 74.8%

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brainly.com/question/14735801

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