Aditya would be the cooler person in this situation I think idk
The concentration of
in the stack gas = 12 ppmv
That means 12 L of
is present per 
The given temperature is 273 K (0 C) and pressure is 1 atm. At these conditions, 1 mol of gas would occupy,


V = 22.4 L
1 mol
occupies 22.4 L
Moles of
= 
Mass of
=
=
μg
Converting
:
= 
Calculating the concentration in μg/
:

Eutrophication results from an excess of
a. phosphates
The mass will increase think of it being on a graph the y axis as mass and x axis as volume density would be the slope of the line so as mass increases so does volume and vise versa
B. oxidizing
In the reaction the oxidizing agent is reduced.