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puteri [66]
3 years ago
8

What should be the first thing human try and research/solve with genetics?

Chemistry
2 answers:
sveta [45]3 years ago
8 0
Es hora de comer. Es hora de comer. Es hora de comer
igor_vitrenko [27]3 years ago
6 0

Genetic disorders that are extremally dehabilitating

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Calculate the amount of solute needed for 1000 ml of 15% sodium thiosulfate
maksim [4K]
15% =  15 grams of solute in 100 mL solution

15 g --------------- 100 mL
?? ------------------ 1000 mL

1000 x 15 / 100 = 

15000 / 100 => 150 g of solute

hope this helps!
7 0
4 years ago
50 + 25 pts 75 for right answer
zheka24 [161]

Answer:

soe are appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many other

Explanation:

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3 years ago
The final acceptor for hydrogen ions in aerobic cellular respiration is
Whitepunk [10]
The appropriate response is oxygen. Cellular respiration is the procedure cells use to make vitality. Cells in our body join glucose and oxygen to make ATP and carbon dioxide. Oxygen is utilized as an electron acceptor inside the electron transport tie of vigorous breath to create adenosine triphosphate or ATP. This compound is a fundamental part in intracellular vitality exchange.
5 0
3 years ago
Which element(s) is being reduced in the redox reaction below? 6 nh4clo4 (s) + 10 al(s) 5 al2o3 (g) + 6 hcl (g) + 3 n2 (g) + 9 h
vitfil [10]
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4 0
3 years ago
The formation of tert-butanol is described by the following chemical equation: (CH3), CBr (aq) + OH(aq) → Br" (aq) +(CH), COH(aq
Dafna11 [192]

Answer:

(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)

Explanation:

There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.

Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.

Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:

(CH_3)_3С^+ (aq) + OH^- (aq)\rightarrow (CH_3)_3COH (aq)

Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:

(CH_3)_3С^+ (aq) + OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + (CH_3)_3C^+ (aq) + Br^- (aq)

Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:

OH^- (aq) + (CH_3)_3CBr (aq)\rightarrow (CH_3)_3COH (aq) + Br^- (aq)

This means we have the correct second step.

6 0
4 years ago
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