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Charra [1.4K]
2 years ago
14

A car moving at a speed of 10 m/s enters a Q. highway and accelerates at 4 m/s2. How fast will the car be moving after it accele

rated for 60m?
answer choices
580 m/s
4.8 m/s
24 m/s
480 m/s m​
Physics
1 answer:
geniusboy [140]2 years ago
5 0
  • Initial velocity=u=10m/s
  • Final velocity=v
  • Acceleration=a=4m/s^2
  • Distance=s=60m

According to third equation of kinematics

\\ \rm\rightarrowtail v^2=u^2+2as

\\ \rm\rightarrowtail v^2=10^2+2(4)(60)

\\ \rm\rightarrowtail v^2=100+480

\\ \rm\rightarrowtail v^2=580

\\ \rm\rightarrowtail v\approx 24m/s

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The maximum torque she can apply to the spark plug is 12.76 Nm.

<h3>What is torque?</h3>

Torque is the rotational equivalent of linear force obtained by taking the product of force and the radius of the applied force.

τ = Fr

where;

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The maximum torque she can apply to the spark plug is calculated as follows;

τ = 58 x (0.22)

τ = 12.76 Nm

Thus, the maximum torque she can apply to the spark plug is 12.76 Nm.

Learn more about torque here: brainly.com/question/14839816

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A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l
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Answer:

c. 0.02 C and 4 J

Explanation:

Applying,

Q = CV................ Equation 1

Where Q = Charge, C = Capacitance of the capacitor, V = Voltage.

From the question,

Given: C = 50 μF = 50×10⁻⁶ F, V = 400 V

Substitute these values into equation 1

Q = (50×10⁻⁶)(400)

Q = 0.02 C.

Also Applying

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