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Maru [420]
3 years ago
7

Joyce paid $39.00 for an item at the store that was 70 percent off the original price. What was the original price?

Mathematics
1 answer:
ladessa [460]3 years ago
8 0

Answer:the answer is 10 because if u subctract it will work

Step-by-step explanation:

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Which situation is represented by the equation x+10=26?
zhuklara [117]

Answer:

16

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can anybody help me with this
kondaur [170]

Answer:

c ≈ 9.1 m

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

c² = 4.1² + 8.1² = 16.81 + 65.61 = 82.42 ( take square root of both sides )

c = \sqrt{82.42 } ≈ 9.1 m ( to the nearest tenth )

5 0
2 years ago
EOC Review
lana [24]

Answer:

0ft and 60ft

Step-by-step explanation:

Given

The attached function

Required

Determine the valid values of the domain of the function

To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).

From the attached graph, the horizontal distance starts from 0 and ends at 180.

This implies that the domain is: 0 \le x \le 180

From the options, the values that fall in this bracket are 0ft and 60ft

3 0
2 years ago
PQR has vertices at P(-10, 8), Q(0, -6),
nirvana33 [79]

Answer:

please apply the formula of distance

l think but not sure

8 0
2 years ago
If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

4 0
2 years ago
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