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3 years ago

Calculate the mass of 4 moles of sodium hydroxide

Chemistry

1 answer:

harina [27]3 years ago

4 0

Answer:

Mass = 160 g

Explanation:

Given data:

Number of moles of sodium hydroxide = 4 mol

Mass of sodium hydroxide = ?

Solution:

Formula:

Mass = number of moles × molar mass of sodium hydroxide

Molar mass of sodium hydroxide = 40 g/mol

Mass = 4 mol × 40 g/mol

Mass = 160 g

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Elements in the third row can break the octet rule

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A solution with a ph of 4 has _________ the concentration of h+ present compared to a solution with a ph of 5.

Marina CMI [18]

A solution with a pH of 4 has ten times the concentration of H⁺ present compared to a solution with a pH of 5.
pH is a numeric scale for the acidity or basicity of an aqueous solution. It is the negative of the base 10 logarithm of the molar concentration of hydrogen ions.
[H⁺] = 10∧-pH.
pH = 4 → [H⁺]₁ = 10⁻⁴ M = 0,0001 M.
pH = 5 → [H⁺]₂ = 10⁻⁵ M = 0,00001 M.
[H⁺]₁ / [H⁺]₂ = 0,0001 M / 0,00001 M.
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3 years ago

27. Sample of neon gas has a pressure of 4.1 atm and argon gas with a pressure of 3.2 atm are added to a

MrRa [10]

Answer:

Option C. 13.5 atm

Explanation:

From the question given above, the following data were obtained:

Pressure of Neon (Pₙₑ) = 4.1 atm

Pressure of Argon (Pₐᵣ) = 3.2 atm

Pressure of nitrogen (Pₙ₂) = 6.2 atm

Total pressure (Pₜ) =?

The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:

Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂

Pₜ = 4.1 + 3.2 + 6.2

Pₜ = 13.5 atm

Therefore, the total pressure in the container is 13.5 atm

8 0

3 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

Answer: The mass of HCl present in 500 mL of acid solution is 36.5 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

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3 years ago

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The given reaction is a combustion reaction, since a hydrocarbon is burning in presence of oxygen

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3 years ago

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