Answer:
Step-by-step explanation:
When we consider Area under arc AC is is representing a quarter as ADBC is a square,
.
Area of quadrant = 
here r= 8 cm
Area under Arc AC= 
Area of white region ABC = Area of square ADBC - Area under Arc AC
![=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2](https://tex.z-dn.net/?f=%3D8%5E2-16%5Cpi%5C%20%5C%20%20%20%20%20%5B%5Ctext%7BArea%20of%20square%7D%20%3D%20sides%5E2%5D%5C%5C%5C%5C%3D%2064-16%5Cpi%5C%20%5C%20%20%3D16%284-%5Cpi%29%5C%20cm%5E2)
Similarly , Area of white region ADC = 
Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

Area of shaded region =
Length of arc AC = 

Perimeter of shaded region = 2(AC) = 
Answer:
yes, because of the Angle-Angle-Angle theorem
scale factor = 2
Step-by-step explanation:
Answer:
m = 3/5
Step-by-step explanation:
Slope Formula: 
Step 1: Find 2 coordinates
(0, 80)
(-50, 50)
Step 2: Find slope <em>m</em>
m = (50 - 80)/(-50 - 0)
m = -30/-50
m = 3/5
It’s A because yea just it is and grabbed
Answer:
A
Step-by-step explanation:
In order for a graph to be a function, it has to only cross the vertical (up and down) lines that it covers once. Since this is an angle, it crosses all the lines in two different places, and isn't a function.