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Ne4ueva [31]
3 years ago
11

The formula of an ionic compound is actually the ___

Chemistry
1 answer:
lidiya [134]3 years ago
7 0

Answer:

r the first one was the first one was the first one was the first one was the first one was w and I have to say it was a great place 33rd and I have to say it was a great place for him ccjfjtjtjgjcfnfjrjru and I think he's a good team and I think he's

Explanation:

  1. d the same thing as the one that I was a great place for me j CV
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Classify each of the following reactions when only the reactants are given and fill in the products.
Nadya [2.5K]

Answer:

CO2 + MgO

Explanation:

We want the number of each element on the Reactants (Left side) to be equal to the number of each element on the Product side (Right side).

3 0
3 years ago
How many particles are in 2.0 moles of CH4
Whitepunk [10]

Answer: There are 4.8 x 1024 hydrogen atoms in 2.0 moles of CH4

6 0
2 years ago
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Water's ability to dissolve a wide variety of molecules is important, but more important is the hydrophobic effect, which drives
Sliva [168]

Answer:

d. Hydrophobic molecules are attracted to each other.

Explanation:

The term “hydrophobic effect” is associated with the spontaneous tendency of macromolecules, such as proteins, to prefer a conformation in an aqueous medium, with hydrophobic groups facing the interior of the mac romolecule, favoring attractive intramolecular interactions, and hydrophilic groups exposed on the surface, for maximize interactions with water molecules in the medium. This is because the hydrophobic molecules are attracted to each other, allowing them to turn inward.

8 0
3 years ago
Which element above has 8 protons in its nucleus?
Nataliya [291]
A. Oxygen. Oxygen has an atomic mass of 16. The atomic mass of an atom is the combined weight o the protons and neutrons. Since Oxygen's atomic mass is 16, it has 8 protons and 8 neutrons.
6 0
3 years ago
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1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
dlinn [17]

Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L

Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol

Substitute these values into equation 4

P = (46/2)(0.082×298)/3

P = (23×0.082×298)/3

P = 187.34 atm

3 0
3 years ago
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