M = 2 . 8 . 2
Valence Electron of M = 2
M ==> M⁺² + 2 e⁻
a. M⁺² + OH⁻ ==> M(OH)₂
b. M⁺² + PO₄⁻³ ==> M₃(PO₄)₂
Hi!
The generic equation showing how a weak base ionizes water is the following:
B(aq) + H₂O(l) ⇄ BH⁺(aq) + OH⁻(aq)
A base is described as weak when its dissociation is difficult and isn't complete. Weak Bases are chemical compounds that accept protons from water, to form the conjugate acid and the OH⁻ ion. The pH of the solution of a weak base is higher than 7. Some weak bases include ammonia (NH₃), Aluminum Hydroxide (Al(OH)₃) and Sodium Acetate (CH₃COONa).
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682mL
Explanation:
Given parameters:
Initial volume of air = 600mL
Initial temperature = 20°C
Final temperature = 60°C
Unknown:
Final volume = ?
Solution:
To solve this problem, we apply Charles's law';
Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "
Mathematically;
V₁ is the initial volume of air
T₁ is the initial temperature of air
V₂ is the final volume of air
T₂ is the final temperature of air
To proceed in solving this problem, we need to convert the given temperature to Kelvin;
T K = 273 + T°C
T₁ = 273 + 20 = 293K
T₂ = 273 + 60 = 333K
now input the parameters;
V₂ = 682mL
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Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa
Answer:
sulfuric acid produces sulfate salts
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