Astronomers use chemical signatures to determine<span> the age and .... </span>Gas<span> mixtures that contain more than </span>4<span>% hydrogen in </span>air<span> are potentially explosive. ... water vapor, </span>carbon dioxide<span>, and several other </span><span>gases</span>
Answer:
Well in one mole of glucose there are 6.022×1023 individual glucose molecules
V2 = 8.6 L
Explanation:
Given:
T1 = 293K. T2 = 314K
V1 = 8.0 L V2 = ?
Using Charles's law and solving for T2,
V1/T1 = V2/T2
V2 = (T2/T1)V1
= (314K/293K)(8.0 L)
= 8.6 L
I don’t understand what your asking
