Answer:
324 people
Explanation:
radius r = diameter / 2 = 45cm /2 = 22.5 cm or 0.225 m
We can calculate the total volume of the log by computing the volume of each cylindrical log:

So the total volume of all 12 logs is

The weight that the raft can support, is the buoyancy force subtracted by its own weight.
The buoyancy force is basically the weight of the water is displaced, which is water density times volume. The log weight is also log density times its volume

where
are the density of water and raft, respectively. But since we have the specific gravity of wood is 0.6. That measn


Therefore 
Let g = 9.8m/s2. We can now calculate the force that the raft can support

Each person has a mass of 68kg, their weight would be
W = 68*g = 68*9.8 = 666.4N
So the maximum number of people that the raft can hold is
F / W = 216129.2 / 666.4 = 324 people
PART A)
As we know that energy of light depends on its wavelength and frequency as following formula

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more
also we know that

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium
PART B)
Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy
When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.
here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current
So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current
I think it would be the one talking about if there’s water there would still be energy because water is used as a source of energy because there’s so much of it and it can be used again and again
M1 = 750Kg, v1 = 10m/s
m2 = 2500Kg , v2= 0 (because in problem say cuz that object don t move).
The momentum before colision is equal with the momentum after colision:
m1v1 + m2v2 = (m1+m2)v3 => v3 is the velocity after colison and that s u want to caluclate for your problem
=> m1v1 = (m1+m2)v3 => v3 = m1v1/(m1+m2) now u should do the math i think v3 prox 2,4 but not sure u should caculate
Answer:
The tension is 75.22 Newtons
Explanation:
The velocity of a wave on a rope is:
(1)
With T the tension, L the length of the string and M its mass.
Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:
(2)
We can equate expression (1) and (2):
=
Solving for T
(3)
For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic
is:

It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:

We can now find T on (3) using all the values we have:

