Answer:
The Percentage concentration of acetic acid = 1.39 %
Explanation:
Density of acetic acid solution = 1.05 g/mL
Volume of acetic acid solution = 0.1 L = 100 mL
From the formula, Density = mass / volume; mass = density × volume
Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g
Molar concentration of acetic acid solution = 0.243 mol/L
Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol
From the formula, mass concentration = molar concentration × molar mass
Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L
In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.
Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%
Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %
The Percentage concentration of acetic acid = 1.39 %
