Answer:
Follow these steps.
1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.
2. Tie the string to the box. Allow the string to hang over the edge of the table.
3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.
4. Add coins one by one until the box is pulled off the table.
5. Count and record the number of coins and the weight of the bag with the coins in it.
6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.
7. Put the matchbox on the rollers farthest from the edge of the table.
8. Now add coins one by one to the bag until the box is pulled off the table.
9. Count and record the number of coins and the weight of the bag with the coins in it.
10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.
11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.
Explanation:
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The ml of 12.0 M HCL needed to prepare 905.0 ml of 1.00m hcl is calculated using M1V1 =M2V2 formula
M1= 12.0 M
V1=?
M2= 905.0 ml
V2 = 1.00M
V1 is therefore = M2V2/M1
=905 x 1.00/12.0 = 75.42 ml
Answer:
Look at explanation
Explanation:
Size of particles increases, rate of reaction decreases, and vise versa
Catalyst causes the rate of reaction to increase
Concentration increases, rate of reaction increases, and vise versa
Temperature increases, rate of reaction increases, and vise versa
Answer:
150.08 g
Explanation:
According the law of conservation of mass, mass can neither be created nor destroyed but is converted from one form to another.
As a result of this, the total mass of reactants must be equal to the total mass of products.
If this is so, we have been told that the mass of AgCl is 150.15 g, the total mass of products is 300.23g.
Therefore; mass of NaNO3 = 300.23 g - 150.15 g = 150.08 g
