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Dominik [7]
3 years ago
9

A student performs an activity to study how electric current flows in a circuit. The student constructs two different circuits,

as shown. The student closes the switches in both circuits. Which table shows the student’s observations and the correct explanations?

Physics
2 answers:
natta225 [31]3 years ago
8 0

Native_Americans_in_the_United_State0000000000000000000000000

Explanation:

alexandr1967 [171]3 years ago
6 0
Eneiwidbfisbesbjaopaoadbfbfhda
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A spring is compressed 0.035 m inside a dart gun. (K=500 N/m). The spring has elastic energy. Calculate it.
NARA [144]

The elastic potential energy of the spring is 0.31 J

Explanation:

The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the compression/stretching of the spring

For the spring in this problem, we have:

k = 500 N/m (spring constant)

x = 0.035 m (compression)

Substituting, we find the elastic potential energy:

E=\frac{1}{2}(500)(0.035)^2=0.31 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
3 years ago
How fast does water flow from a hole at the bottom of a very wide, 3.2 m deep storage tank filled with water
Nezavi [6.7K]

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

The computation of the velocity of the water flow is as follows

Here we use the Bernouli equation

As we know that

V_1 = \sqrt{2g(h_2 - h_1)}\\\\=\sqrt{2g(\Delta h)}  \\\\= \sqrt{2\times9.8\times3.2} \\\\= \sqrt{62.72}

= 7.92 m/s

Hence, the velocity of the water flow is 7.92 m/s

We simply applied the above formula so that the correct value could come

And, the same is to be considered

5 0
3 years ago
A motorboat traveling 4 m/s, East encounters a current traveling 3.0 m/s, North. a) What is the resultant velocity of the motorb
Nostrana [21]

Explanation:

It is given that,

Velocity in East, v_1=4\ m/s

Velocity in North, v_2=3\ m/s

(a) The resultant velocity is given by :

v=\sqrt{4^2+3^2}=5\ m/s

(b) The width of the river is, d = 80 m

Let t is the time taken by the boat to travel shore to shore. So,

t=\dfrac{d}{v}

t=\dfrac{80\ m}{5\ m/s}

t = 16 seconds

(c) Let x is the distance covered by the boat to reach the opposite shore. So,

x=v_2\times t

x=3\ m/s\times 16\ s

x = 48 meters

Hence, this is the required solution.

4 0
3 years ago
suppose you increase your walking speed from 4 m/s to 12 m/s in a period of 1 second what is your acceleration
KiRa [710]

a   = 12 ms⁻¹ - 4ms⁻¹ / 1 s

a  =    8 ms⁻²

7 0
3 years ago
10. Calculate the kinetic energy of a running back that has a mass of 80 kg and
EastWind [94]

Answer:

The answer is

<h2>2560 J</h2>

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass

v is the velocity

From the question

m = 80 kg

v = 8 m/s

The kinetic energy is

KE =  \frac{1}{2}  \times 80 \times  {8}^{2}  \\  = 40 \times 64

We have the final answer as

<h3>2560 J</h3>

Hope this helps you

5 0
2 years ago
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