Explanation:
Given that,
Frequency in the string, f = 110 Hz
Tension, T = 602 N
Tension, T' = 564 N
We know that frequency in a string is given by :
, T is the tension in the string
i.e.
, f' is the another frequency
f' =106.47 Hz
We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :
So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.