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Leviafan [203]
2 years ago
15

Give the name of the products formed

Chemistry
1 answer:
attashe74 [19]2 years ago
7 0

Answer:

With Br2 - Bromobenzene

With Cl2 - Chlorobenzene

With HNO3- Nitrobenzene

With H2SO4 - Benzenesulphonic acid

With HCOCl - Benzoyl chloride

With 1-chloro-2,2-dimethylpropane - 2,2dimethyl-1-phenyl propane

Explanation:

The common thread joining all these reactions is that they are all electrophillic reactions. They are so called because the attacking agents in each reagent is an electrophile. Electrophiles are species that have electron deficient centers and are known to attack molecules that are high in electron density at regions of high electron density.

The benzene molecule has rich electron density. Any substituents that donates electrons to the ring improves the likelihood that benzene will undergo electrophillic substitution reactions while electron withdrawing substituents decrease the likelihood that benzene will undergo electrophillic substitution reactions.

The names of the compounds formed when benzene undergoes electrophillic reaction with the attacking agents listed in the question are displayed in the answer section.

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The pH of a saturated solution of a metal hydroxide MOH is 10.15. Calculate the Ksp for this compound.
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Answer:

Ksp=2.00x10^{-8}

Explanation:

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In this case, since the pH of the given metal is 10.15, we can compute the pOH as shown below:

pOH=14-pH=14-10.15=3.85

Now, we compute the concentration of hydroxyl ions in solution:

[OH^-]=10^{-pOH}=10^{-3.95}=1.41x10^{-4}M

Now, since this hydroxide has the form MOH, we infer the concentration of OH- equals the concentration of M^+ at equilibrium, assuming the following ionization reaction:

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Therefore, the Ksp for the saturated solution turns out:

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2 years ago
What is the most basic level of biological organization?
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The estimate obtained from a sample of which size is likely to be closest to
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A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 ​ , 1.09 g h 2 ​ o, and 1.70 g n 2 ​ . if the molar mass of th
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m(N₂) = 1,70 g.
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n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
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n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
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