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ycow [4]
3 years ago
15

Name the homologous series for this compound and show its structurech3ch2cc(ch2)2ch3​

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

Alkyne

Explanation:

The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.

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P.1 is a variant of SARS-CoV2. This is the so-called "Brazil variant". It has the amino acid the substitution N501Y in the spike
Free_Kalibri [48]

Answer:

more negative

Explanation:

There are various variants of Coviid virus. The Brazilian variant P also known as Gamma variant is the third variant of the original SARS-CoV2. This variant has raised concerns since it has ability to spread more quickly then previous variants and this is more negative variant. It is assumed that Coviid variant Gamma and Delta has ability to absorb move UV light but this is not proved yet and research is underway.

7 0
3 years ago
Determine the mass density, specific volume and specific weight of a liquid whose
irakobra [83]

the volume is 63 i hope it is

5 0
3 years ago
The charge on an ion is known as its___number.
a_sh-v [17]

Answer:

oxidation number is correct!! :)

Explanation:

8 0
3 years ago
Look at the equation CO2 + H2 = CO + H20.
sergejj [24]

Answer:

CO is considered as a product.

Explanation:

A general chemical equation for a combination reaction follows:

To write a chemical equation, we must follow some of the rules:

The reactants must be written on the left side of the direction arrow.

A '+' sign is written between the reactants, when more than one reactants are present.

An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.

The products must be written on the right side of the direction arrow.

A '+' sign is written between the products, when more than one products are present.

For the given chemical equation:

are the reactants in the reaction and  are the products in the reaction.

Hence, CO is considered as a product.

3 0
3 years ago
How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = 87.5^{o}C = (87.5 + 273) K = 360.5 K

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}

Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

5 0
3 years ago
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