If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al
1 answer:
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Answer :
The name of is ammonium chloride.
The name of is iron(III) nitrate.
The name of is titanium(III) bromide.
The name of is copper(I) phosphide.
The name of is tin(IV) selenide.
The name of is gallium arsenide.
The name of is lead(IV) sulfate.
The name of is beryllium hydrogen carbonate.
The name of is manganese(III) sulfite.
The name of is aluminium cyanide.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(a)
It is an ionic compound because it is formed by the combination of one polyatomic cation (ammonium ion) and anion (chloride ion). The charge on ammonium ion is (+1) and the the charge on chloride ion is (-1).
Thus, the name of is ammonium chloride.
(b)
It is an ionic compound because it is formed by the combination of one polyatomic anion (nitrate ion) and cation (iron ion). The charge on iron ion is (+3) and the the charge on nitrate ion is (-1).
Thus, the name of is iron(III) nitrate.
(c)
It is an ionic compound because it is formed by the combination of titanium cation and bromide anion. The charge on titanium is (+3) and the the charge on bromide ion is (-1).
Thus, the name of is titanium(III) bromide.
(d)
It is an ionic compound because it is formed by the combination of copper cation and phosphorous anion. The charge on copper is (+1) and the the charge on phosphorous ion is (-3).
Thus, the name of is copper(I) phosphide.
(e)
It is an ionic compound because it is formed by the combination of tin cation and selenium anion. The charge on tin is (+4) and the the charge on selenium ion is (-2).
Thus, the name of is tin(IV) selenide.
(f)
It is an ionic compound because it is formed by the combination of gallium cation and arsenic anion. The charge on gallium is (+3) and the the charge on arsenic ion is (-3).
Thus, the name of is gallium arsenide.
(g)
It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfate ion) and cation (lead ion). The charge on lead ion is (+4) and the the charge on sulfate ion is (-2).
Thus, the name of is lead(IV) sulfate.
(h)
It is an ionic compound because it is formed by the combination of one polyatomic anion (hydrogen carbonate ion) and cation (beryllium ion). The charge on beryllium ion is (+2) and the the charge on hydrogen carbonate ion is (-1).
Thus, the name of is beryllium hydrogen carbonate.
(i)
It is an ionic compound because it is formed by the combination of one polyatomic anion (sulfite ion) and cation (manganese ion). The charge on manganese ion is (+3) and the the charge on sulfite ion is (-2).
Thus, the name of is manganese(III) sulfite.
(j)
It is an ionic compound because it is formed by the combination of one polyatomic anion (cyanide ion) and cation (aluminium ion). The charge on aluminium ion is (+3) and the the charge on cyanide ion is (-1).
Thus, the name of is aluminium cyanide.