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alexandr1967 [171]
3 years ago
14

If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al

+ 3 F₂ → 2 AlF₃
Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

You will need 12.0 moles of F₂

Explanation:

Based on the chemical equation, 2 moles of AlF₃ are produced when 3 moles of F₂ are added in an excess of Al.

Using this expression: 2mol AlF₃ = 3mol F₂ we can find the moles of F₂ as follows:

8.00 mol AlF₃ * (3mol F₂ / 2mol AlF₃) =

<h3>You will need 12.0 moles of F₂ </h3>
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Answer:

             Height  = 1.9493 cm

             Width =  1.9493 cm

             Depth  =  1.9493 cm

Solution:

Data Given:

                  Mass  =  20 g

                  Density  =  2.7 g/mL

Step 1: Calculate the Volume,

As,

                                        Density  =  Mass ÷ Volume

Or,

                                        Volume  =  Mass ÷ Density

Putting values,

                                        Volume  =  20 g ÷ 2.7 g/mL

                                        Volume  =  7.407 mL or 7.407 cm³

Step 2: Calculate Dimensions of the Cube:

As we know,

                                        Volume  =  length × width × depth

So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.

Hence,

                                        Volume  =  1.9493 cm × 1.9493 cm × 1.9493 cm

                                        Volume  =  7.407 cm³

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3 years ago
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