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alexandr1967 [171]
3 years ago
14

If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al

+ 3 F₂ → 2 AlF₃
Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

You will need 12.0 moles of F₂

Explanation:

Based on the chemical equation, 2 moles of AlF₃ are produced when 3 moles of F₂ are added in an excess of Al.

Using this expression: 2mol AlF₃ = 3mol F₂ we can find the moles of F₂ as follows:

8.00 mol AlF₃ * (3mol F₂ / 2mol AlF₃) =

<h3>You will need 12.0 moles of F₂ </h3>
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Answer:

92.6

Explanation:

6 mol x 18.02 g of H2o --> 3 mol x 58.33 g  Mg(OH)2

108.12 g of h2o --> 174.99 of Mg(OH)2

g of H2O is 150 g of Mg(OH)2

150g x 108.12g / 174.99 =

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3 years ago
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Explanation:

The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.

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We have 3 moles of nitrogen here,

So, 6 moles of ammonia will be form

so from the formula

no of moles=mass/atomic mass

           mass= no. of moles*atomic mass

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                       = 102 grams of ammonia will be formed.

So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.

7 0
4 years ago
Suppose you place a ball in the middle of a wagon, and then accelerate the wagon forward. Describe the motion of the ball relati
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