The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
Alkali Metals have 2 valence electrons
PbCl2 and PbCl4
Empirical formula is when the molecular formula is reduced (each element) by the same number until you are unable to do so any further.
CH2O cannot be further reduced, but C3H6O3 can all be divided by 3 making it CH2O (same empirical formula)
Mi opinión es false but I'm sure I’m sorry my friend
Molecular orbital energy is the energy associated with each electron in an atom or molecule.
It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.
C2+: Molecular Orbital Energy Diagram
1s2 2s2 2p2
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 0 e-
π2p* ← 0 e-
π2p ← 0 e-
Bond Order: 0
Stability: Unstable
Magnetism: Diamagnetic (no unpaired electrons)
O2-: Molecular Orbital Energy Diagram
1s2 2s2 2p4
σ2s* ← 0 e-
σ2s ← 2 e-
σ2p* ← 0 e-
σ2p ← 2 e-
π2p* ← 0 e-
π2p ← 2 e-
Bond Order: 1
Stability: Stable
Magnetism: Paramagnetic (2 unpaired electrons)
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