What would be a rule to help you identify foods containing carbohydrates?

Chemistry

1 answer:

abruzzese [7]4 years ago

5 0

Answer:

In order to help identify foods containing carbohydrates,

-Anything that contains sugar, starch, or cellulose is a carbohydrate.

-Anything that contains fiber is a carbohydrate.

-Anything that is derived from plants is a carbohydrate.

-Anything that contains dairy or gluten is a carbohydrate.

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Five moles of sulfur dioxide, soz, would consist of how many molecules?<br> molecules<br> Need Help?

Amiraneli [1.4K]

Answer:

3 x 10²⁴ molecules

Explanation:

A mole is just a name that we use to substitute a number, just like a dozen means 12, a mole means 6.022 x 10²³. This gives us the unit conversion of 6.022 x 10²³ molecules SO₂/1 mol SO₂.

$5molSO2*\frac{6.022 x 10^2^3molecules}{1mol SO2} = 3.011 x 10^2^4moleculesSO2$

Round to the lowest number of significant figures to get 3 x 10²⁴ molecules SO₂

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4 years ago

Suppose you are given an unknown solid material. Describe some tests you might perform to prove that is either an element or a c

nikitadnepr [17]

<span>An element is a pure substance that cannot be broken down by further chemical techniques. Therefore you could try heating, cooling, electrolysis or other methods to see if it was an element or a compound.</span>

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3 years ago

What is the force being applied to an object with a mass of 12 KG and an acceleration of 4M/S

mario62 [17]

Answer:

48 newtons

Explanation:

f=m*a

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3 years ago

A chemist adds of a sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemi

schepotkina [342]

This is a incomplete question.The complete question is:

A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: 50.4 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$ .....(1)