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Vikki [24]
3 years ago
8

If the lungs of a child hold 0.11 mol of air in a volume of 2.8 L, then the lungs of an average female adult, with a volume is 4

.6 L, can be expected to hold 0.18 mol of air.
show work
Chemistry
1 answer:
Aleks [24]3 years ago
4 0

Answer:

Explanation:

A childs lung can hold .11mols/ per 2.8 L so that gives us a molarity of .039M

A adults lungs can hold .18 mols /per 4.6 so that gives us .039M aswell meaining that the lung capacity between the two is not different.

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A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
NeTakaya

Answer:

solubility of X in water at 17.0 ^{0}\textrm{C} is 0.11 g/mL.

Explanation:

Yes, the solubility of X in water at 17.0 ^{0}\textrm{C} can be calculated using the information given.

Let's assume solubility of X in water at 17.0 ^{0}\textrm{C} is y g/mL

The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.

So, solubility of X in 1 mL of water = y g

Hence, solubility of X in 36.0 mL of water = 36y g

So, 36y = 3.96

   or, y = \frac{3.96}{36} = 0.11

Hence solubility of X in water at 17.0 ^{0}\textrm{C} is 0.11 g/mL.

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