The final image formed after shifting the object will be virtualand erect image and formed at a distance of behind the mirror.
Further Explanation:
Given:
The magnification of the image for the object placed at from the mirror is .
The final distance of the object from the mirror is .
Concept:
The magnification of the image for the object placed at from the mirror is .
The magnification of the image can be represented as.
Substitute for and for in above expression.
Here, the image distance is equal to the object distance. In case of the mirror, the image distance and the object distance are equal only when the object is placed at the centre of curvature of the mirror.
Therefore, the focal length of the mirror will be half of the distance of the object from the mirror.
Now, the object is shifted towards the mirror. The new distance of the object from the mirror is .
The mirror’s formula can be expressed as.
Substitute for and for in above equation.
The image distance is positive. It means that the final image of the object will be formed behind the mirror i.e. the image will be virtual.
The magnification of the image is.
Thus, <u>the image formed will be erect, virtual and three times the size of the object.
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Answer Details:
Grade: Middle School
Chapter: Mirror’s Formula
Subject: Physics
Keywords: Image distance, object distance, mirror’s formula, magnification, 30 cm from the mirror, now moved 20cm, ray diagram, real inverted.