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Mnenie [13.5K]
4 years ago
5

A blue car with mass mc = 427 kg is moving east with a speed of vc = 20 m/s and collides with a purple truck with mass mt = 1282

kg that is moving south with a speed of vt = 13 m/s . The two collide and lock together after the collision. Let us define to the east is the +x direction and to the north is the +y direction. What is the magnitude of the initial momentum of the car?
Physics
1 answer:
polet [3.4K]4 years ago
6 0

Answer:8540 kg-g/s

Explanation:

Given

mass of blue car m_c=427 kg

velocity of blue car v_c=20 m/s

mass of the truck m_t=1282 kg

speed of truck v_t=13 m/s

After collision they stick and lock together

Let v be the velocity of combined system at angle \theta from vertical

Conserving momentum in east direction

m_c\times v_c=(m_c+m_t)v\cos \theta

427\times 20 =1709\times v\cos \theta------1

Conserving Momentum in Y direction

m_t\times v_t=(m_c+m_t)v\sin \theta

1282\times 13 =1709\times v\sin \theta-------2

squaring and then adding 1 & 2 we get

(8540)^2+(16666)^2=(1709)^2\cdot v^2

v=10.95 m/s

initial momentum of car=427\times 20=8540 kg-m/s

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