The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.
<h3>What is power?</h3>
Power is the energy transferred per unit time.
Torque is find out by
P = 2πNT/60
10000 = 2π x 2000 x T / 60
T =47.74 N.m
The gear ratio Ne / Ns =4/1
Ns =2000/4 = 500
Ts =Ps x 60/(2π x 500)
Ts =190.96 N.m
Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))
τ max =T/J x D/2
where d₁ = 30mm = 0.03 m
d₀ = 30 +(2x 4) = 38mm =0.038 m
Substitute the values into the equation, we get
τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)
τ max = 28.98 MPa.
Thus, the maximum shear stress in the tube is 28.98 MPa.
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Answer: the final temperature of the steam 581.5 °C
Explanation:
Given that;
P₁ = 11 MPa
T₁ = 600°C
exit at; P₂= 5.5 MPa
Now from superheated steam table( p=11 MPa, T=600°C)
h₁ = 3615 kJ/kg
h₁ = h₂ ( by throttling process and adiabatic isentholpic )
from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )
Temperature = 581.5 °C
Therefore the final temperature of the steam 581.5 °C
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