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2 years ago

Can the MOXIE created by NASA be used on earth

Engineering

1 answer:

Alisiya [41]2 years ago

4 0

Answer:

MOXIE is designed to generate up to 10 grams of oxygen per hour. This technology demonstration was designed to ensure the instrument survived the launch from Earth, a nearly seven-month journey through deep space, and touchdown with Perseverance on Feb

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Technician A says that hoods are designed with reinforcements to prevent folding during a collision. Technician B says that some

-BARSIC- [3]

Technician A is wrong.

Usually, hoods have what is called "Crush Zones" underneath the panels. The function of the Crush Zone is to prevent the hoods, during a collision, from entering into the passenger space.

The crush zones allow the hoods to fold instead.

Technician B is right.

Automobile producers now make use of a hybrid form of hood that consists of fiberglass reinforced with plastic.

They are mostly used for trucks that have a low volume of production.

The hood is built using a process called Resin Transfer Model (RTM).

See the link below for more about automobile engineering:

brainly.com/question/4822721

6 0

2 years ago

When a variable is stored in memory, it is associated with an address. To obtain the address of a variable, the & operator c

liubo4ka [24]

Answer:

Explanation:

1) C program file addressOfScalar.c

#include <stdio.h>

int main()

{

//intialize a char variable, print its address and the next address

char charvar = 'a';

printf("address of charvar = %p\n", (void *)(&charvar));

printf("address of charvar - 1 = %p\n", (void *)(&charvar - 1));

printf("address of charvar + 1 = %p\n", (void *)(&charvar + 1));

//intialize a int variable, print its address and the next address

int intvar = 1;

printf("address of intvar = %p\n", (void *)(&intvar));

printf("address of intvar - 1 = %p\n", (void *)(&intvar - 1));

printf("address of intvar + 1 = %p\n", (void *)(&intvar + 1));

}

In C programming language, an int variable takes 4 bytes of memory. So any arithmetic on integer address, always considers it as 4 bytes of data. So intvar-1 refers to a location 4 bytes before intvar's address and intvar+1 refers to 4 bytes after intvar's address.

3 0

3 years ago

The water in a 25-m-deep reservoir is kept inside by a 140-m-wide wall whose cross section is an equilateral triangle as shown i

koban [17]

Answer: (a) 9.00 Mega Newtons or 9.00 * 10^6 N

(b) 17.1 m

Explanation: The length of wall under the surface can be given by

$b=25m/sin(60)\\=28.867$

The average pressure on the surface of the wall is the pressure at the centeroid of the equilateral triangular block which can be then be calculated by multiplying it with the Plate Area which will provide us with the Resultant force.

$F(resultant) = Pavg ( A) = (Patm + \rho g h c)*A \\= [100000 N/m^2 + (1000 kg/m^3 * 9.81 m/s^2 * 25m/2)]* (140*25m/sin60)\\= 8.997*10^8 N \\= 9.0*10^8 N$

Noting from the Bernoulli equation that

$Po/\rho g sin60 = 100000/1000 * 9.81* sin(60) = 11.77 m \\ \\$

From the second image attached the distance of the pressure center from the free surface of the water along the surface of the wall is given by:

$Yp = s+\frac{b}{2} +\frac{b^2}{s+\frac{b}{2}+Po/\rho g sin60}= 0+\frac{28.87}{2} +\frac{28.87^2}{0+\frac{28.87}{2}+100000 /1000 *9.81 sin60} = 17.1 m$

Substituting the values gives us the the distance of the surface to be equal to = 17.1 m

7 0

3 years ago

Explain combined normal and shear stresses with sketch. Write the general expression for (a) Normal and shear stresses on inclin

Alborosie

Answer:

a) Normal stress :

бn =[ ( бx + бy ) / 2 + ( бx - бy ) / 2 ] cos2∅ + Txysin2∅

shear stress

Tn = ( - бx - бy ) / 2 sin2∅ + Txy cos2∅

b) principal stress :

б1 = ( бx + бy ) / 2 - $\sqrt{}$ ( ( бx - бy ) / 2 )^2 + T^2xy

maximum shear stress:

Tmax = ( б1 - б2) / 2 = √ (( бx - бy ) / 2 )^2 + T^2xy

Explanation:

Combined normal stress and shear stress sketches attached below

The terms in the sketch are :

бx = tensile stress in x direction

бy = tensile stress in y direction

Txy = y component of shear stress acting on the perpendicular plane to x axis

бn = Normal stress acting on the inclined plane EF

Tn = shear stress acting on the inclined plane EF

A) Normal and shear stresses on inclined plane

Normal stress :

бn =[ ( бx + бy ) / 2 + ( бx - бy ) / 2 ] cos2∅ + Txysin2∅

shear stress

Tn = ( - бx - бy ) / 2 sin2∅ + Txy cos2∅

B) principal and maximum shear stresses

principal stress :

б1 = ( бx + бy ) / 2 - $\sqrt{}$ ( ( бx - бy ) / 2 )^2 + T^2xy

maximum shear stress:

Tmax = ( б1 - б2) / 2 = √ (( бx - бy ) / 2 )^2 + T^2xy

6 0

2 years ago

PLEASE QUICK!!!!!!!!!!! Overtime people have given names to groups of stars called_____

kirza4 [7]

Answer:

Constellations

Explanation:

Constellations describes a group of stars that appear to form a pattern or a picture. Example of common patterns are : Leo the Lion or Orion the Great Hunter. It is easy to recognize constellations and most people will tend to orient with these patterns. There are 88 patterns currently known.

6 0

3 years ago